Question 20 Set up the integral that calculates the area of the region enclosed by the circle x2 + y = 4² and the horizontal line y = 2/3 in the upper half plane (y 2 0), using polar coordinates. 2/3 1 (16-12 sec2(0)) de a) O S/6 b) O /6 (16 - 12 csc (@) dô 2R/3 5(16 – 12 csc (0) do c) O n/3 • 2x/3 1 (16 – 12 csc (0) dð d) O 5x/6 o) (16-12 sec" () do e) O 5a/6 1 f) O (16 – 12 sec (0) do g) ONone of the above.

Q: Find the area under the polar curve r = cos(0) – sin(0) between the lines 0 = 0 and 0 = 4 5.

A:

Q: 1.5 3-y QI) Evaluate the integral dx dy using polar coordinate

A:

Q: Consider the polar curve r=2+ cos O (a) Sketch the curve (b) Set up and then evaluate an integral to…

A:

Q: 4. a) Find the points of intersection of the polar curves r = 1 and r² = 2 sin(20) b) Find the area…

A: Ok

Q: sin(6) and y = -x, (2) Compute the area of the highlighted region R between r = drawn in polar…

A: Here intersection line y=-x and circle r=sinθ is r=0 to π4therefore A=12∫0π4(sinθ)2dθ…

Q: For the rose r = 4 sin(20) and circle r = 2 shown in the figure. Find the area inside the rose and…

A:

Q: Find the area of the Polar Region located in the interior of the graph of r = 8 - sint A = 2√²/²2…

A: The polar equation r=8-sint Graph

Q: 2 9-x sin (x? +y² ) dy dx 2 sin x +y 2 9-x 3.

A:

Q: nates. 7) Evaluate the iterated integral 23 /9-xx sin (x² + y²) dy dx by converting to polar coordi-

A: