Question 2. Vibrational and rotational spectroscopy A. Calculate the reduced mass for 14N¹60 and its moment of inertia with a bond length of 127 pm.

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A: Note:  1 l = 10 dl = 1000 cc 1 kg = 1000 g 1 ml = 1000 ul 1 cc = 1 ml 100 cc = 1 dl

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A: Step 1: Given equation is:  1×10−14=(6.4×10−8+x)x x2+(6.4×10−8)x−10−14=0 ⇒x2+1086.4x​−10−141​=0 Tip:…

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Q: 1.85kg - 127g adding and subtracting problems chemistry

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Q: DES OOOT DOST 2000 (D) 000€ her all t

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Q: 14. 1 picometer = A) 1 x 1010 centimeters B) 1 x 10-10 C) 1 x 108 D) 1 x 10-8 E) 1 x 10-12

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Q: 1. For the reaction below: a. b. Predict the products and show the mechanism using curved arrows.…

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A: (6.266 − 6.261) ÷ 522.0 = ( 0.005) ÷ 522.0 = 9.579 x 10-6  Number of significant figures are 4.

Q: 2What is the specific gravity of a 5.0 L syrup weighing 6.565 Kg?   a 1.313   b 0.762   c 0.76…

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Q: (2.6*10^-6)*(2.02*10^4)

A: (2.6*10^-6)*(2.02*10^4) = =(2.6×10-6) × (2.02×104)=(2.6×2.02) × 10-6+4=5.25×10-2

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