Question 2 The important industrial chemical, vinyl chloride, can be made by the reaction between acetylene and hydrogen chloride: C2H2(g) + HCl(g) → CH2=CHCl(g) A suitable catalyst is mercury(II) chloride. The reaction produces substantial amounts of heat and the reaction vessel is water-cooled. a. Calculate ∆??R ° at 25 °C for the complete reaction of 1.00 mol of hydrogen chloride. b. Hence calculate ∆??R ° at 25 °C for the complete reaction of 1.00 kg of hydrogen chloride. c. Calculate the amount (in moles) and mass (in kg) of cooling water that would be needed to keep the reaction vessel at 25 °C, if the water were initially at 10 °C. d. Calculate the amount (in moles) and volume (in cubic metres) of C2H2 at a pressure of 200 kPa and a temperature of 25 °C that would be required to react with 1.00 kg of hydrogen chloride. You may assume C2H2 to be a perfect gas. Data: ∆?f (298 K) for C2H2 (g) = 226.73 kJ mol–1 ∆?f (298 K) for HCl(g) = –92.31 kJ mol–1 ∆?f(298 K) for CH2=CHCl(g) = 35.5 kJ mol–1 ?? for H2O(l) = 75.291 J K–1 mol–1

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Chapter1: Chemical Foundations
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Question 2
The important industrial chemical, vinyl chloride, can be made by the reaction between
acetylene and hydrogen chloride:
C2H2(g) + HCl(g) → CH2=CHCl(g)
A suitable catalyst is mercury(II) chloride. The reaction produces substantial amounts of heat
and the reaction vessel is water-cooled.
a. Calculate ∆??R
° at 25 °C for the complete reaction of 1.00 mol of hydrogen chloride.
b. Hence calculate ∆??R
° at 25 °C for the complete reaction of 1.00 kg of hydrogen chloride.
c. Calculate the amount (in moles) and mass (in kg) of cooling water that would be needed
to keep the reaction vessel at 25 °C, if the water were initially at 10 °C.
d. Calculate the amount (in moles) and volume (in cubic metres) of C2H2 at a pressure of
200 kPa and a temperature of 25 °C that would be required to react with 1.00 kg of
hydrogen chloride. You may assume C2H2 to be a perfect gas.

Data:
∆?f (298 K) for C2H2 (g) = 226.73 kJ mol–1
∆?f (298 K) for HCl(g) = –92.31 kJ mol–1
∆?f(298 K) for CH2=CHCl(g) = 35.5 kJ mol–1
?? for H2O(l) = 75.291 J K–1 mol–1 

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