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Question 2 Suppose P=NP. Mark all statements that follow from this. Clique is decidable in polynomial time. There is a k > 0 such that, for every problem A in NP, A is decidable in time O(nk). For every problem A in NP, there is a k > 0 such that A is decidable in time O(nk). Every problem A in NP is decidable in time O(n10). SAT is decidable in polynomial time.

Question 2 Suppose P=NP. Mark all statements that follow from this. Clique is decidable in polynomial time. There is a k > 0 such that, for every problem A in NP, A is decidable in time O(nk). For every problem A in NP, there is a k > 0 such that A is decidable in time O(nk). Every problem A in NP is decidable in time O(n10). SAT is decidable in polynomial time.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question 2 Suppose P=NP. Mark all statements that follow from this. Clique is decidable in polynomial time. There is a k > 0 such that, for every problem A in NP, A is decidable in time O(n*). For every problem A in NP, there is a k > 0 such that A is decidable in time O(nk). Every problem A in NP is decidable in time O(n10). O SAT is decidable in polynomial time.
Transcribed Image Text:Question 2 Suppose P=NP. Mark all statements that follow from this. Clique is decidable in polynomial time. There is a k > 0 such that, for every problem A in NP, A is decidable in time O(n*). For every problem A in NP, there is a k > 0 such that A is decidable in time O(nk). Every problem A in NP is decidable in time O(n10). O SAT is decidable in polynomial time.
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