Question 2 of 15 A transformer is used to supply voltage to a neon sign. The primary voltage on the transformer is 120 V and the sign needs a voltage of 12,000 V. What is the ratio of the number of secondary to primary windings in the transformer, Ns/Np?

College Physics
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Author:Paul Peter Urone, Roger Hinrichs
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Chapter23: Electromagnetic Induction, Ac Circuits, And Electrical Technologies
Section: Chapter Questions
Problem 50PE: A large power plant generates electricity at 12.0 kV. Its old transformer once converted the voltage...
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### Question 2 of 15

A transformer is used to supply voltage to a neon sign. The primary voltage on the transformer is 120 V and the sign needs a voltage of 12,000 V. What is the ratio of the number of secondary to primary windings in the transformer, \( N_s / N_p \)?

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**Explanation:**
This question pertains to the basic functionality of a transformer, which is to change the level of voltage from one side to the other through electromagnetic induction. The ratio of the number of turns (or windings) on the primary coil (\( N_p \)) to the secondary coil (\( N_s \)) is directly related to the ratio of the voltages.

In mathematical terms, the ratio can be expressed by the formula:

\[ \frac{N_s}{N_p} = \frac{V_s}{V_p} \]

Where:
- \( N_s \) is the number of turns on the secondary coil,
- \( N_p \) is the number of turns on the primary coil,
- \( V_s \) is the secondary voltage,
- \( V_p \) is the primary voltage.

Given values:
- \( V_p = 120 \) V
- \( V_s = 12,000 \) V

Substitute the values into the formula to find the ratio \( \frac{N_s}{N_p} \):

\[ \frac{N_s}{N_p} = \frac{12,000}{120} = 100 \]

Thus, the ratio of the number of secondary windings to primary windings in the transformer is \( 100:1 \).
Transcribed Image Text:### Question 2 of 15 A transformer is used to supply voltage to a neon sign. The primary voltage on the transformer is 120 V and the sign needs a voltage of 12,000 V. What is the ratio of the number of secondary to primary windings in the transformer, \( N_s / N_p \)? --- **Explanation:** This question pertains to the basic functionality of a transformer, which is to change the level of voltage from one side to the other through electromagnetic induction. The ratio of the number of turns (or windings) on the primary coil (\( N_p \)) to the secondary coil (\( N_s \)) is directly related to the ratio of the voltages. In mathematical terms, the ratio can be expressed by the formula: \[ \frac{N_s}{N_p} = \frac{V_s}{V_p} \] Where: - \( N_s \) is the number of turns on the secondary coil, - \( N_p \) is the number of turns on the primary coil, - \( V_s \) is the secondary voltage, - \( V_p \) is the primary voltage. Given values: - \( V_p = 120 \) V - \( V_s = 12,000 \) V Substitute the values into the formula to find the ratio \( \frac{N_s}{N_p} \): \[ \frac{N_s}{N_p} = \frac{12,000}{120} = 100 \] Thus, the ratio of the number of secondary windings to primary windings in the transformer is \( 100:1 \).
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