Question 2 of 15 A transformer is used to supply voltage to a neon sign. The primary voltage on the transformer is 120 V and the sign needs a voltage of 12,000 V. What is the ratio of the number of secondary to primary windings in the transformer, Ns/Np?
Question 2 of 15 A transformer is used to supply voltage to a neon sign. The primary voltage on the transformer is 120 V and the sign needs a voltage of 12,000 V. What is the ratio of the number of secondary to primary windings in the transformer, Ns/Np?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Question 2 of 15
A transformer is used to supply voltage to a neon sign. The primary voltage on the transformer is 120 V and the sign needs a voltage of 12,000 V. What is the ratio of the number of secondary to primary windings in the transformer, \( N_s / N_p \)?
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**Explanation:**
This question pertains to the basic functionality of a transformer, which is to change the level of voltage from one side to the other through electromagnetic induction. The ratio of the number of turns (or windings) on the primary coil (\( N_p \)) to the secondary coil (\( N_s \)) is directly related to the ratio of the voltages.
In mathematical terms, the ratio can be expressed by the formula:
\[ \frac{N_s}{N_p} = \frac{V_s}{V_p} \]
Where:
- \( N_s \) is the number of turns on the secondary coil,
- \( N_p \) is the number of turns on the primary coil,
- \( V_s \) is the secondary voltage,
- \( V_p \) is the primary voltage.
Given values:
- \( V_p = 120 \) V
- \( V_s = 12,000 \) V
Substitute the values into the formula to find the ratio \( \frac{N_s}{N_p} \):
\[ \frac{N_s}{N_p} = \frac{12,000}{120} = 100 \]
Thus, the ratio of the number of secondary windings to primary windings in the transformer is \( 100:1 \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F83bd02c6-d02f-4764-a848-15fcab9c3f4f%2F469767e2-93f8-4452-9db3-292d57df4e51%2Fsyurkom_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question 2 of 15
A transformer is used to supply voltage to a neon sign. The primary voltage on the transformer is 120 V and the sign needs a voltage of 12,000 V. What is the ratio of the number of secondary to primary windings in the transformer, \( N_s / N_p \)?
---
**Explanation:**
This question pertains to the basic functionality of a transformer, which is to change the level of voltage from one side to the other through electromagnetic induction. The ratio of the number of turns (or windings) on the primary coil (\( N_p \)) to the secondary coil (\( N_s \)) is directly related to the ratio of the voltages.
In mathematical terms, the ratio can be expressed by the formula:
\[ \frac{N_s}{N_p} = \frac{V_s}{V_p} \]
Where:
- \( N_s \) is the number of turns on the secondary coil,
- \( N_p \) is the number of turns on the primary coil,
- \( V_s \) is the secondary voltage,
- \( V_p \) is the primary voltage.
Given values:
- \( V_p = 120 \) V
- \( V_s = 12,000 \) V
Substitute the values into the formula to find the ratio \( \frac{N_s}{N_p} \):
\[ \frac{N_s}{N_p} = \frac{12,000}{120} = 100 \]
Thus, the ratio of the number of secondary windings to primary windings in the transformer is \( 100:1 \).
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