QUESTION 2 In communication system, the tuned Radio Frequency signal x[n] that you receive is not x[n] but normally is y[n] due to the surrounding effect, where the expression is shown in the following equation 2 1 x[n] → x[n] -지n- 1] + 지n-2] → yln] The goal is to compute the inverse filter g[n] that recovers x[n] from y[n], so that g[n] undoes the effect of h[n]. The flow is as stated: x[n] → h[n] → y[n] → g[n] → x[n] Find G[z] and g[n]. Hint: The overall impulse response of the systems in cascade is the convolution of their impulse responses. So we want h[n]* g[n]= 8[n], which implies H[z]G[z] = 1.

QUESTION 2 In communication system, the tuned Radio Frequency signal x[n] that you receive is not x[n] but normally is y[n] due to the surrounding effect, where the expression is shown in the following equation 2 1 x[n] → x[n] -지n- 1] + 지n-2] → yln] The goal is to compute the inverse filter g[n] that recovers x[n] from y[n], so that g[n] undoes the effect of h[n]. The flow is as stated: x[n] → h[n] → y[n] → g[n] → x[n] Find G[z] and g[n]. Hint: The overall impulse response of the systems in cascade is the convolution of their impulse responses. So we want h[n]* g[n]= 8[n], which implies H[z]G[z] = 1.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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QUESTION 2 In communication system, the tuned Radio Frequency signal x[n] that you receive is not x[n] but normally is y[n] due to the surrounding effect, where the expression is shown in the following equation x[n] → x[n] -3지[n-1] +교n-2]-yln] The goal is to compute the inverse filter g[n] that recovers x[r] from y[n], so that g[r] undoes the effect of h[n]. The flow is as stated: x[n] – h[n] – y[n] – g[n] → x[n] Find G[z] and g[n]. Hint: The overall impulse response of the systems in cascade is the convolution of their impulse responses. So we want h[n]*g[n] =&[n]. which implies Hz]G[2] = 1.