☐ Question 2 If w = 2y² + uy + (2u + v) sin(xz) then the value of sin(dw) at x = −0.4070, y = 0.7907, z = −1.7789, u = -3.9960, v = −2.7422, dx = 0.0936, dy = 0.0769, dz = −0.0441, du = 0.0534, dv = -0.0257, is 04438 1 pts O 0.4438 O 0.4235 0.9413 O -0.1458 0.2856 0.5375 -0.2688 O 0.7315

Q: Differentiate. f(0) = 0 cos(0) sin(0)

A:

Q: 3 4) Find / sin (2x) cos (2x)dx

A:

Q: (5) If y = sin(3x) the find y"

A: We have given trigonometric equation  y=sin3x y'=dydx y'=ddxsin3x y'=cos3x·ddx3x y'=3cos3x…

Q: Evaluate ㅠ * 0 sin (9x) sin(5x) dx.

A: To evaluate the following integral.∫0π sin9x sin5x dx

Q: -. Solve for dy/dx a. y = *+ sinx cos x † Sin X

A:

Q: dx xVx -1 6.

A:

Q: 2. 2 | sin xcos xdx

A:

Q: sin (3x+1)dx 4 cos (3x+1) C

A:

Q: Find sin (x) if sec (x) sin (x) A = B = B = 26 24' where tan > 0. Put your answer in reduced form.

A:

Q: 4. sin2xcosx + sin x 1 xE[-27, Zn]

A:

Q: d (x2+2x)(sin(x)+5) 7. Find: dx Зx+2

A: To find:

Q: solve for y'. y=sin-1[(ax+b)/(bx+a)]

A: Sin-1x can be written as asin(X)   So we have expression as y=sin-1(ax+b)(bx+a) We have to solve for…

Q: y = sin (3x)

A:

Q: cos(In x) dx =? A 1/(sin 1) B sin 1 1/(cos 1) D sin(e)

A: Given integral can be evaluated as shown below

Q: S (|sin x| + sin æ') dx

A:

Q: 3. √9-x2 dx (hint: sin x = S dx (hint: sinx = (sin²x)(sin²x)) x4

A:

Q: 1. de 2-3 sin(0)

A:

Q: | sin x (3cos*)dx 2:

A:

Q: Evaluate (tanx * dy/dx) - у %3D а a. y = -a + C(cscx) ОБ. None of the choices О с. у%3-а+ C (cosx) O…

A:

Q: 3. S sin? (2t) cos³ (2t) dt 4. ſ tan³(3x)dx

A:

Q: 1. x2 cos 2x dx

A: The given integral is: ∫x2cos 2x dx