QUESTION 2: How much Pareactant will be needed to produce 105.8g of tetraphosphorus decaoxide (P4010)? G: 105.8g P4010 мM: 1 тol Pa010 — 287.88g Р,010 1 mol P4 = 127.88g P4 MR: 3 тol P,01о — Зтоl Р, СHOICES: A. 74g P4 B. 0.74g P4 С. 47g Ра D. 0.047g P4
QUESTION 2: How much Pareactant will be needed to produce 105.8g of tetraphosphorus decaoxide (P4010)? G: 105.8g P4010 мM: 1 тol Pa010 — 287.88g Р,010 1 mol P4 = 127.88g P4 MR: 3 тol P,01о — Зтоl Р, СHOICES: A. 74g P4 B. 0.74g P4 С. 47g Ра D. 0.047g P4
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Chapter1: Chemical Foundations
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![QUESTION 2: How much Pareactant will be needed to produce 105.8g of tetraphosphorus decaoxide
(P4010)?
G: 105.8g P4010
мм: 1 тol P,010 3D 287.88g P,010
1 тol P, 3D 127.88g Р,
MR: 3 тol P,01о — Зтоl Р,
СHOICES:
A. 74g P4
В. 0.74g Ра
С. 47g Ра
D. 0.047g P4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F46a194d3-5915-46cd-b446-0ac37fba61e8%2F5226162c-c4c7-4ec4-8db6-290bff410f01%2F907y6ng_processed.png&w=3840&q=75)
Transcribed Image Text:QUESTION 2: How much Pareactant will be needed to produce 105.8g of tetraphosphorus decaoxide
(P4010)?
G: 105.8g P4010
мм: 1 тol P,010 3D 287.88g P,010
1 тol P, 3D 127.88g Р,
MR: 3 тol P,01о — Зтоl Р,
СHOICES:
A. 74g P4
В. 0.74g Ра
С. 47g Ра
D. 0.047g P4
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