Question 2: Gauss' Law For this problem we will consider the surface of a rectangular prism shown to the right with one corner at the origin. Given an electric field of E = (z²-5z)k calculate the total charge enclosed in the surface. 3cm 1cm y 2cm (0) 19
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- A closed surface with dimensions a=b=D0.40 m and c=0.60 m is located as in the figure below. The left edge of the closed surface is located at position x= a. The electric field in the region is non-uniform and is given by E=(3.0+ 44x2 ) i N/C, where x is in meters. Calculate the net electric flux leaving the closed surface? b- Select one: OA. 5.91 O B. 1.41 OC. 14,71 OD. 4.22 OE 10.31Figure 3 shows six planes which are put together to form a cuboid. Determine the total charge enclosed by the cuboid using Gauss's Law if electric flux density is given as D = 3x²a, + y²â, + 2z²a, C/m². (1, 3, 2) (3, -2, 0) (3, 3, 0) Unit: m Figure 3A closed surface with dimensions a = b = 0.400 m and c = 0.800 m is located as shown in the figure below. The left edge of the closed surface is located at position x = a. The electric field throughout the region is non-uniform and given by E = [ (yz2)i + (xz2+2)j +(2xyz-1)k] N/C, where x,y are in meters. Find the magnitude and direction of Efield at the point (0.5m,0.6m) Calculate the flux through each surface. What net charge is enclosed by the surface
- The volume charge density of a spherical charge distribution is given by rho(r) = rho0 e^(-ar), where rho0 and a are constants. What is the electric field produced by this charge distribution? (Enter the radial component of the electric field. Use the following as necessary: rho0, a, r, and E0.)need help