Question 2: For the footing given below, calculate the ultimate bearing capacity (qu or qf) and net ultimate bearing capacity (qns) of the footing given below using General Bearing Capacity Equation. General shear failure occurs in the soil and the relevant information are given below. There is no ground water level. It has been observed that resultant load acting on the footing is vertical. However, resultant load creates an eccentricity (only one-way eccentricity), therefore, a moment. The eccentricity is e = 0.5 m le Df = 3 m бт х бт Soil c' = 3 kPa o' = 30° Ym = 19 kN/m³ Center Line

Question 2: For the footing given below, calculate the ultimate bearing capacity (qu or qf) and net ultimate bearing capacity (qns) of the footing given below using General Bearing Capacity Equation. General shear failure occurs in the soil and the relevant information are given below. There is no ground water level. It has been observed that resultant load acting on the footing is vertical. However, resultant load creates an eccentricity (only one-way eccentricity), therefore, a moment. The eccentricity is e = 0.5 m le Df = 3 m бт х бт Soil c' = 3 kPa o' = 30° Ym = 19 kN/m³ Center Line

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter16: Soil Bearing Capacity For Shallow Foundations

Section: Chapter Questions

Problem 16.5P: Redo Problem 16.1 using the modified general ultimate bearing capacity Eq. (16.31). 16.1 A...

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Question 2: For the footing given below, calculate the ultimate bearing capacity (qu or qf) and net ultimate bearing capacity (4nf) of the footing given below using General Bearing Capacity Equation. General shear failure occurs in the soil and the relevant information are given below. There is no ground water level. It has been observed that resultant load acting on the footing is vertical. However, resultant load creates an eccentricity (only one-way eccentricity), therefore, a moment. The eccentricity is e = 0.5 m D, = 3 m 6m * 6m Soil c' = 3 kPa o' = 30° Ym = 19 kN/m³3 Center Line
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Redo Problem 16.1 using the modified general ultimate bearing capacity Eq. (16.31). 16.1 A continuous footing is shown in Figure 16.17. Using Terzaghis bearing capacity factors, determine the gross allowable load per unit area (qall) that the footing can carry. Assume general shear failure. Given: = 19 kN/m3, c = 31kN/m2, =28, Df = 1.5 m, B = 2 m, and factor of safety = 3.5. Figure 16.17
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