QUESTION 2 Determine the value of P just sufficient to start the 62° wedge under the W lb blue block. The angle of friction is p for all contact surfaces. Neglect the weight of the orange block. The surface numbers are in light green highlight P OND 2 01

Q: -3 ft- -4 ft- 60 B 1.5 ft 500 ft-lb D 1.5 ft

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Q: mins. and (p)r-02m.

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Q: PLEASE DO THIS TYPEWRITTEN ONLY FOR UPVOTES. DO THIS ASAP

A: Given data in question Loads Span member length  Dimensions  To find out  REaction at joint A

Q: Calculate the member forces of the loaded structure. y 60 kN D 40 kN 7 m C, 3 m Ax Ay -4 m-

A:

Q: Find MG

A: Data given Find : Metacentric height

Q: 0.6 m - 0.6 m → 0.6 m -- 0.6 m 900 N/m 50° B Cl 2

A:

Q: under the following boundary conditions (x = 0, y = 0); (x = L, y = yMax). what kind of beam is…

A: Beams can also be described with their boundary conditions. In the given question,  When x=0…

Q: Determine the x-coordinate of the centroid of the shaded area. y x=ky a O A. 3b/10 O B. 2b/7 OC.…

A: To find x - coordinate of centroid

Q: - In the cross section below, find:-

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Q: Find the position of the centroid as well as the moment of inertia with respect to a horizontal axis…

A: Given:

Q: N N Z+

A:

Q: Column2 700mm 1 3m Beam2 4 3. 700mm+ Column1- 3 3 1 +350+ . 4 350 15. 2 2 2 Beam3 5m Beam1 1 11 4m…

A: Volume of BEAM 1= (4-0.35/2-1.050/2)*0.35*0.45= 3.3*0.35*0.45= 0.51975= 0.52 m3 Volume of BEAM 2=…

Q: Calculate the polar radius of gyration of the shaded area about its centroid C. Assume t=115 mm, a…

A:

Q: Find force BE And EC

A: Given Data:Span AE= 3mSpan ED= 3mLoad on B= 5kNLoad on C= 5kNBC=CD

Q: 25KN 3M lookN 3M の

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Q: 11-2 Why does a spiral improve the behavior of a column?

A: A spiral is a continuous winding of steel reinforcement in the form of a helix around the…

Q: 0.115=(1.483-3tan@)-(1,368-33 tan®)

A: answer angle = 179.04 degree

Q: 400 N 2m 2m 2 m 45 P 2m

A: Note: As nothing is mentioned in this question so we are assuming that we have to calculate support…

Q: Find R1

A: Given data : The value of point load P=20 KN The value of point load Q=30 KN The value of point load…

Q: Q2) T= (50-20) 38²) A horizontal distance of (500 m) must be lay out with a steel tape, length of…

A: Given: Length of steel tape  Temperature  Measured distance  Pull  Area  To find: Correct horizontal…

Q: Llä 8 The table below is the page of a level field book. Fill in the missing reading and calculate…

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Q: A (150,100) 442) H O B (190, 210) A2.330° T 25th TG M (2305100) ↑ ( (280) 100) Compute the area of…

A: Given:

Q: The distance from C to X

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Q: 2/40 The 30-N force P is applied perpendicular to the portion BC of the bont bar. Dotermino the…

A: Calculate the bending moment at point B due to load P Moment (MB)= Force×perpendicular…

Q: ) pind L, and し。 a b) find H

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Q: Determine the force-couple system acting at point 0. 50 N 90 N 40° В 40 N m 400 mm 1300 mm A 4 800…

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Q: Example Replace the force and couple system shown by an equivalent resultant force and couple moment…

A: Replace the force and couple system shown by an equivalent resultant force and couple moment acting…

Q: -1 m 260 N B I _im- 320 N/m -1.7 m 200 N -0.8 m E

A:

Q: For the beam shown in Fig.Q4, use the principle of virtual work to determine (1) the vertical…

A:

Q: ?근 d=0:02 m 7m Lalom Uso-2% Frnd Z 2.

A: Given:pressure at point 1    P1=104 KN/m2  and HEad Z1=7 m   and velocity V1=0at point 2    P2=0…

Q: 6 m B 4 m E D 6 m 6 m

A: Given: P1 = 36 kN P2 = 46 kN A = 300 mm2 E = 300 GPa

Q: Column2 3m 700mm+ 1 Column1- 3 Beam2 4 3 A 700mm+ 3 1 4 +350 + P 3 1 350. 2 2 2 Beam3 5m Beam1 1 2…

A: Quantities Beam 1 Beam 2 Beam 3 Length (m) 3.3  2.475 4.125  Width (m) 0.35 0.35 0.35 Depth…

Q: Q5// Locate the centriod (xe.ye) for the shaded area shown in figure 5. 1cm 1cm 1pm 2cm 2cm (Figure…

A:

Q: Q2) On an inclined surface frictionless, snow covered, a skier has a speed of 45 mph at the bottom…

A: Speed of the skier = v  = 45mph or 100.655m/secLength of sloped surface = 300ft. or…

Q: Locate the centroid of the shaded area. 4 m 1 16 -8 m- y = 4- - [+] X 2 X

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Q: O WRITE SHEAR * MOMENT * DRAW SHEAR EQUATIONS S MOMENT DIAGRAMS, 20KN A Im 4 C 3m R. 13

A: Calculation of reaction forces-R1+R2=12×3×20R1+R2=30       eq 1

Control Survey and Geodetic reductions

Control surveys or survey controls are used to establish reference points as a basis for various construction activities. Vertical and horizontal control points are to be established in a control survey to increase accuracy. After establishing the control points, all other types of surveys such as topographic, right-of-way, aerial mapping, construction layout, boundary surveys, and utility mapping can be worked upon so that control networks can be formed. The place from which the observations are made is called a survey station.