Question 2: Consider the system shown in the figure below. The frames have 8,000 bits, ACKs are negligible in size, and the frame processing time is negligible at intermediate nodes. The speed of light in the fiber is 200,000 Km/sec. 40 Kbps 0.5 sec RTT Wireless 10 Mbps 100 Km Fiber 40 Kbps 0.5 sec RTT Wireless A B a) Assume that the frame transmission is error-free. Find the effective data throughput from A to B when each wireless link uses Stop and Wait. Hint: The effective data throughput through the system is equal to that of the bottleneck link. b) Repeat the calculation assuming now that Stop and Wait is used on the complete path between A and B. Assume for questions c and d that the wireless links each have a BER of 1×10-5, the ACK transmissions are error free, and the fiber link is error free. Note: when the wireless links are not error free, the achievable throughput drops to (1-FER) multiplied by the error free effective data throughput of the system, where FER is the frame error rate. c) Find the Frame Error Rate (FER), then find the effective data throughput from A to B when each wireless link uses Stop and Wait. d) When Stop and Wait is used on the complete path between A and B, the Frame is error free if there is no error during the first wireless transmission and there is no error during the second wireless transmission. Find the Frame Error Rate FER in this case, then find the effective data throughput from A to B assuming now that Stop and Wait is used on the complete path between A and B.
Question 2: Consider the system shown in the figure below. The frames have 8,000 bits, ACKs are negligible in size, and the frame processing time is negligible at intermediate nodes. The speed of light in the fiber is 200,000 Km/sec. 40 Kbps 0.5 sec RTT Wireless 10 Mbps 100 Km Fiber 40 Kbps 0.5 sec RTT Wireless A B a) Assume that the frame transmission is error-free. Find the effective data throughput from A to B when each wireless link uses Stop and Wait. Hint: The effective data throughput through the system is equal to that of the bottleneck link. b) Repeat the calculation assuming now that Stop and Wait is used on the complete path between A and B. Assume for questions c and d that the wireless links each have a BER of 1×10-5, the ACK transmissions are error free, and the fiber link is error free. Note: when the wireless links are not error free, the achievable throughput drops to (1-FER) multiplied by the error free effective data throughput of the system, where FER is the frame error rate. c) Find the Frame Error Rate (FER), then find the effective data throughput from A to B when each wireless link uses Stop and Wait. d) When Stop and Wait is used on the complete path between A and B, the Frame is error free if there is no error during the first wireless transmission and there is no error during the second wireless transmission. Find the Frame Error Rate FER in this case, then find the effective data throughput from A to B assuming now that Stop and Wait is used on the complete path between A and B.
Chapter8: Data And Network Communication Technology
Section: Chapter Questions
Problem 1PE
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