Question 2: By Newton forward method find the value of (el.85) given e¹7 = 5.4739, 1.8-6.0496, el.⁹-6.6859, e20-7.3891, e²¹ = 8.1662 e

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Chapter2: Second-order Linear Odes
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Question 2:
By Newton forward method find the value of (e¹.85) given e¹7 = 5.4739,
1.9
el.86.0496, e¹9 = 6.6859, e2.0= 7.3891,
e².¹-8.1662
=
Transcribed Image Text:Question 2: By Newton forward method find the value of (e¹.85) given e¹7 = 5.4739, 1.9 el.86.0496, e¹9 = 6.6859, e2.0= 7.3891, e².¹-8.1662 =
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