Question 2: Answer the following question stretched string fixed at each ends has a mass of 50 g and a length of 8 m. When the tension in the string is 49 N, it produces a a standing wave of 3 harmonics L The position of the 3rd Node from the left in (m) = The position of the 2nd Antinode from the left in (m) = Question 3: Conclusion 1. If the number of harmonics of the vibrating string (wire) of the sonometer is 4, then the number of antinodes formed is + ↑
Question 2: Answer the following question stretched string fixed at each ends has a mass of 50 g and a length of 8 m. When the tension in the string is 49 N, it produces a a standing wave of 3 harmonics L The position of the 3rd Node from the left in (m) = The position of the 2nd Antinode from the left in (m) = Question 3: Conclusion 1. If the number of harmonics of the vibrating string (wire) of the sonometer is 4, then the number of antinodes formed is + ↑
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter17: Sound
Section: Chapter Questions
Problem 85P: A nylon guitar string is fixed between two lab posts 2.00 m apart. The string has a linear mass...
Related questions
Question
![III
4G!!!
14
Question 2: Answer the following
question
stretched string fixed at each ends has a mass of 50
g and a length of 8 m. When the tension in the string
is 49 N, it produces a a standing wave of 3
harmonics
11:1.
The position of the 3rd Node from the left in (m) =
The position of the 2nd Antinode from the left in (m)
◆
Question 3: Conclusion
1. If the number of harmonics of the vibrating string
(wire) of the sonometer is 4, then the number of
antinodes formed is
moodle.nct.edu.om](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F30d03a3f-f276-4f36-b8d4-1006b5a56441%2F504914e8-3a83-4c3f-8076-8185d6cf3843%2Fg3d3xkd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:III
4G!!!
14
Question 2: Answer the following
question
stretched string fixed at each ends has a mass of 50
g and a length of 8 m. When the tension in the string
is 49 N, it produces a a standing wave of 3
harmonics
11:1.
The position of the 3rd Node from the left in (m) =
The position of the 2nd Antinode from the left in (m)
◆
Question 3: Conclusion
1. If the number of harmonics of the vibrating string
(wire) of the sonometer is 4, then the number of
antinodes formed is
moodle.nct.edu.om
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