Question 2 An electron is observed traveling at a speed of 24.5 x 10-6 m/s parallel to a constant electric field of magnitude 10000 N/C. A. Draw as system schema.
Q: Starting from rest, a proton is accelerate through constant electric field. After travelling a…
A: mass of proton m = 1.67 × 10-27 kg distance traveled =48 cm = 0.48 m Initial speed u = 0 Final…
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Q: QUESTION 3 Consider the situation shown in the figure: at a certain instant of time a point particle…
A: 3) Change Q = +25μc at (0,0,0) velocity of charge V→ = 3 * 106 m/s j^ position vector of point P…
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A: Separation distance between the proton is d = 5.29 x 10-11 m
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Q: QUESTION 5 A particle with a charge of 7.7 µC and a mass of 0.00022 kg is fired horizontally with a…
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Q: LA-1 A proton is released at rest in an electric field E-450N/C. Neglect the effect of the weight of…
A: Given that Initial velocity of the proton (v1) =0 Final velocity is (v2) =1.50x106m/s Electric field…
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Q: 7. A proton is released from rest at point A in a uniform electric field that has a magnitude of…
A: electric field = E = 5 X 104 V/mdisplacement = d = 0.5 mcharge of proton = q = 1.6 x 10-19 Cmass of…
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Q: Problem 7 An electron is placed in a uniform electric field of 0.15 N/C. Assume that the velocity of…
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A: Given: Electric field, E = 510 N/C time, t = 47 ns
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- 52 A proton enters the uniform electric field produced by the two charged square plates shown below. The plates carry charges +Qand-Q, where the magnitude Q=1.6 µC. The speed of the proton when it enters the region between the plates is 5 x 107 m/s. 12.0 cm- Figure Description Hint a. What is the magnitude of electric field in the region? Assume that the plates are close enough together to be treated as "infinite" planes for electric field between them. N/C. b. What distance d has the proton been deflected downward when it leaves the region between the two plates? Assume that the electrostatic force is the only force on the charge. I # 3 E= d Question Help: Message instructor Submit Question 80 F3 E $ 4 800 F4 27 5° cm. 5 F5 R T 6 MacBook Air F6 Y & 7 > F7 U * CO 8 DII F8 - ( 9 F9 0 ) O F10Retarding E Field An electron with a speed of v= 6 x 107 m/s enters an electric field of magnitude E = 2 x 10³ N/C, traveling along the field lines in the direction that retards its motion. Emily Smith - PHGN200, Spring 2021 - Intro to E&M Sample Exam I Questions from Fall 2011 How far will the electron travel in the field before stopping momentarily? 63)An electron with speed 2.15×107 m/s is traveling parallel to a uniform electric field of magnitude 1.15×104 N/C . Part A How far will the electron travel before it stops? Part B How much time will elapse before it returns to its starting point?
- The figure shows an electric dipole. What is the magnitude of the dipole's electric field at point P? Assume that q = 9.85 x 106 C,d= 6.97 x 10-6 m, and r = 0.403 cm. +q+ Number i 9440530.064 N/C or V/m d/2 d/2 -9 Units1- An electron with a speed of 2.0 × 10 6 m/s moves into a uniform electric field of 550 N/C that is parallel to the electron’s motion. How long does it take to bring the electron to rest? ( m e = 9.11 × 10 −31 kg, e = 1.6 × 10 −19 C)A proton is fired from very far away directly at a fixed particle with charge q = 1.90 x 10-18 C. If the initial speed of the proton is 1.9 x 105 m/s, what is its distance of closest approach to the fixed particle? The mass of a proton is 1.67 x 10-27 kg. X The correct answer is not zero. m Submit Answer
- 58. A proton accelerates from rest in a uniform electric field of 640 N/C. At some time later, its speed is 1.20 x 10° m/s. a. What is the magnitude of the acceleration of the proton? b. How long does it take the proton to reach this speed? c. How far has it moved in this time interval? d. What is its kinetic energy at the later time?-6.0 x 10¹5 C N >E 2.0 m - 6.0 x 105 C 3.0 m 4.0 x 10-5C A 9₂ 3.0 m 2.0 m 2 -3.0 x 10-5 C • A a. Determine the net electric field at point A. b. The magnitude of the electric field due to each charge, (i.e. calculate 1 and ₂), at point A. a. For each part in practice question 1, find the net force on a -1.2 × 10-5 C charge placed at point A. b. How would your answer change if the sign of the charge from 2a at point A was changed?