Question 2 An electric circuit consists of a battery (voltage source) connected to a resistor and capacitor in series. The resulting ordinary differential equation for the voltage on the capacitor Vc(t) is as follows: We will use the values (b) Vin function dVc Vin dt RC = = R VR 1 RC satisfies the ODE and the initial condition. 1 1000 C= 0.001 Vo = 9 Here resistance R is in Ohms, time t is in seconds, capacitance C is in Farads, and voltage Vin is in Volts. Initially, the voltage on the capacitor is zero: Vc (0) = 0. (a) Assume the resistance is constant: R Vc(t). = Vc T O Vc(t)= 9(1e-10t) 100. Check by direct substitution that the Now assume that the resistor slowly degrades, so that its resistance increases with time: R = R(t) = 100 + 2t.
Question 2 An electric circuit consists of a battery (voltage source) connected to a resistor and capacitor in series. The resulting ordinary differential equation for the voltage on the capacitor Vc(t) is as follows: We will use the values (b) Vin function dVc Vin dt RC = = R VR 1 RC satisfies the ODE and the initial condition. 1 1000 C= 0.001 Vo = 9 Here resistance R is in Ohms, time t is in seconds, capacitance C is in Farads, and voltage Vin is in Volts. Initially, the voltage on the capacitor is zero: Vc (0) = 0. (a) Assume the resistance is constant: R Vc(t). = Vc T O Vc(t)= 9(1e-10t) 100. Check by direct substitution that the Now assume that the resistor slowly degrades, so that its resistance increases with time: R = R(t) = 100 + 2t.
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Transcribed Image Text:Question 2
An electric circuit consists of a battery (voltage source) connected to a resistor and capacitor in series.
The resulting ordinary differential equation for the voltage on the capacitor Vc(t) is as follows:
We will use the values
(b)
Vin
function
dVc
dt
+
-
+
C = 0.001
Vin
1
RC RC
-
R
VR
satisfies the ODE and the initial condition.
1
1000'
Vo = 9
Here resistance R is in Ohms, time t is in seconds, capacitance C is in Farads, and voltage Vin is in Volts.
Initially, the voltage on the capacitor is zero: Vc(0) = = 0.
(a)
Assume the resistance is constant: R
Vc(t).
=
Vc
Q
Vc(t) = 9(1-e-10t)
100. Check by direct substitution that the
Now assume that the resistor slowly degrades, so that its resistance increases with time:
= R(t) =
= 100 + 2t.
R=
Solve the ordinary differential equation for Vc(t) with this resistance, using either separation of
variables, or the integrating factor method. Make sure to also include the initial condition.
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