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Question 2 a. For the principal quantum number n=4, write out all possible values of I, and based on these: write values of m, m 0,1,2,3,4 -4,-3, -2, -1, 0, 1, 2, 3, +4 b. Put all of the orbitals you identified in part (a) in the order of increasing energy according to the Aufbau process. Use the designations 1s, 2s etc for this question. You may include orbitals for which n>4 in order to complete the series. 1s, 2s, 2p, 3s, 3p, 3d, 4s, 4p, 4d, 4f, 4g c. For an ion with 2+ charge , where the outermost electrons have quantum numbers n=4, 1 = 2. If there are 6 electrons in this outermost subshell, what element does this correspond to? Explain your answer. n= 4, 1 = 2 corresponds to the 4d subshell If there are 6 electrons in the 4d shell, and the ion has 2+ charge, it means that the neutral element would have 2 more electrons. This means that the electron configuration of the neutral element is [Kr] 5s24d, The element is Palladium (Pd).

Question 2 a. For the principal quantum number n=4, write out all possible values of I, and based on these: write values of m, m 0,1,2,3,4 -4,-3, -2, -1, 0, 1, 2, 3, +4 b. Put all of the orbitals you identified in part (a) in the order of increasing energy according to the Aufbau process. Use the designations 1s, 2s etc for this question. You may include orbitals for which n>4 in order to complete the series. 1s, 2s, 2p, 3s, 3p, 3d, 4s, 4p, 4d, 4f, 4g c. For an ion with 2+ charge , where the outermost electrons have quantum numbers n=4, 1 = 2. If there are 6 electrons in this outermost subshell, what element does this correspond to? Explain your answer. n= 4, 1 = 2 corresponds to the 4d subshell If there are 6 electrons in the 4d shell, and the ion has 2+ charge, it means that the neutral element would have 2 more electrons. This means that the electron configuration of the neutral element is [Kr] 5s24d, The element is Palladium (Pd).

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Page 3 of 3 ZOOM Question 2 a. For the principal quantum number n=4, write out all possible values of I, and based on these: write values of m, mi 0,1,2,3,4 -4,-3, -2, -1, 0, 1, 2, 3, +4 b. Put all of the orbitals you identified in part (a) in the order of increasing energy according to the Aufbau process. Use the designations 1s, 2s etc for this question. You may include orbitals for which n>4 in order to complete the series. 1s, 2s, 2p, 3s, 3p, 3d, 4s, 4p, 4d, 4f, 4g c. For an ion with 2+ charge , where the outermost electrons have quantum numbers n=4, / = 2. If there are 6 electrons in this outermost subshell, what element does this correspond to? Explain your answer. n= 4, / = 2 corresponds to the 4d subshell If there are 6 electrons in the 4d shell, and the ion has 2+ charge, it means that the neutral element would have 2 more electrons. This means that the electron configuration of the neutral element is [Kr] 5s24d8. The element is Palladium (Pd). MacBook Air +
Transcribed Image Text:Page 3 of 3 ZOOM Question 2 a. For the principal quantum number n=4, write out all possible values of I, and based on these: write values of m, mi 0,1,2,3,4 -4,-3, -2, -1, 0, 1, 2, 3, +4 b. Put all of the orbitals you identified in part (a) in the order of increasing energy according to the Aufbau process. Use the designations 1s, 2s etc for this question. You may include orbitals for which n>4 in order to complete the series. 1s, 2s, 2p, 3s, 3p, 3d, 4s, 4p, 4d, 4f, 4g c. For an ion with 2+ charge , where the outermost electrons have quantum numbers n=4, / = 2. If there are 6 electrons in this outermost subshell, what element does this correspond to? Explain your answer. n= 4, / = 2 corresponds to the 4d subshell If there are 6 electrons in the 4d shell, and the ion has 2+ charge, it means that the neutral element would have 2 more electrons. This means that the electron configuration of the neutral element is [Kr] 5s24d8. The element is Palladium (Pd). MacBook Air +
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