QUESTION 2A researcher wants to find out whether a gender difference exists in life satisfaction. Analyse the following results.Variables:- Gender (male - female)- Life satisfaction (QG4A LIFE SATISFACTION) "How satisfied are you with your life in general?" (1 - 10:1= completely dissatisfied, 5=exactly halfway, 10=completely satisfied)Group StatisticsQG4A LIFESATISFACTIONQG4A LIFESATISFACTIONSEX OF RESPONDENTMALEFEMALEEqual variancesassumedEqual variances notassumedN383541Meani7,817,88FStd. Deviation1,6231,868Levene's Test for Equality ofVariances.3,328Sig.Independent Samples Test,068Std. ErrorMeanWhich of the following statements is correct?O The null hypothesis for the Levene's Test states that equal variances are not assumedt-,542-,556,083,080O Life satisfaction is significantly higher for females compared to malesO When reporting our output, we would write down that the degrees of freedom equals 922O Here, the Levene's Test rejects the null hypothesisdf Sig. (2-tailed)922,588884,287,579t-test for Equality of Means.MeanDifference-,064-,064Std. ErrorDifference11811595% Confidence Interval of theDifferenceLower-,296-,291Upper,168,162

Answered: QUESTION 2 A researcher wants to find…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Periodically, customers of a financial services company are asked to evaluate the company's financial consultants and services. Higher ratings on the client satisfaction survey indicate better service, with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use ? = 0.05 and test to see whether the consultant with more experience has the higher population mean service rating. Assume the population variances are unequal. Consultant A Consultant B n1 = 16 n2 = 10 x1 = 6.85 x2 = 6.25 s1 = 0.69 s2 = 0.75 (a) State the null and alternative hypotheses. -H0:?1 − ?2 = 0 Ha:?1 − ?2 = 0 -H0:?1 − ?2 > 0 Ha:?1 − ?2 = 0 -H0:?1 − ?2 ≠ 0 Ha:?1 − ?2 = 0 -H0:?1 − ?2 = 0 Ha:?1 − ?2 > 0 -H0:?1 − ?2 = 0 Ha:?1 − ?2 ≠ 0 (b) Compute the value of the test statistic. (Round your answer to three decimal places.)…
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Answer A & B
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