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Question 2 (a) Figure 3 shows the positive shunt clipper circuit. Analvze., the output ya wavefor the negative of sinusoidal waveform of -10V with suitable diode position. 10 V 10 k2 -10 V Figure 3 (b) Analvze the output voltage va and the output waveform for the configuration shov Figure 4. 100 V Ideal diodes -100 V 2.2 ka Figure 4 (c) Figure 5 shows the Halfwave rectifier. Analyze, the output voltage, Vour. current, I, the waveform of the output, Vout for two circuit above. Given the transformer to ha 12 V rms secondary voltage for the standard 120 V across the primary. Examine the output voltage for the Bridge rectifier with the practical model, and calculate the Inverse Voltage (PIV) required for the diodes. +5 V +100 V- V. 0 IN4001 IN4003 -5V---- -100 V- 1Ok

Question 2 (a) Figure 3 shows the positive shunt clipper circuit. Analvze., the output ya wavefor the negative of sinusoidal waveform of -10V with suitable diode position. 10 V 10 k2 -10 V Figure 3 (b) Analvze the output voltage va and the output waveform for the configuration shov Figure 4. 100 V Ideal diodes -100 V 2.2 ka Figure 4 (c) Figure 5 shows the Halfwave rectifier. Analyze, the output voltage, Vour. current, I, the waveform of the output, Vout for two circuit above. Given the transformer to ha 12 V rms secondary voltage for the standard 120 V across the primary. Examine the output voltage for the Bridge rectifier with the practical model, and calculate the Inverse Voltage (PIV) required for the diodes. +5 V +100 V- V. 0 IN4001 IN4003 -5V---- -100 V- 1Ok

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question 2 (a) Figure 3 shows the positive shunt clipper circuit. Analze. the output ya waveform for the negative of sinusoidal waveform of -10V with suitable diode position. 10 V I k2 10 k2 v. -10 V Figure 3 (b) Analvze the output voltage ya and the output waveform for the configuration shown in Figure 4. 100 V Ideal diodes -100 V 2.2 k2 Figure 4 (c) Figure 5 shows the Halfwave rectifier. Analyze, the output voltage, Vou. current, I, label the waveform of the output, Vout for two circuit above. Given the transformer to have a 12 V rms secondary voltage for the standard 120 V across the primary. Examine the peak output voltage for the Bridge rectifier with the practical model, and calculate the Peak Inverse Voltage (PIV) required for the diodes. +5 V- +100 V V. 0 V. 0 IN4001 IN4003 -5 V--- -100 V--- 1Okf 1.0k Figure 5
Transcribed Image Text:Question 2 (a) Figure 3 shows the positive shunt clipper circuit. Analze. the output ya waveform for the negative of sinusoidal waveform of -10V with suitable diode position. 10 V I k2 10 k2 v. -10 V Figure 3 (b) Analvze the output voltage ya and the output waveform for the configuration shown in Figure 4. 100 V Ideal diodes -100 V 2.2 k2 Figure 4 (c) Figure 5 shows the Halfwave rectifier. Analyze, the output voltage, Vou. current, I, label the waveform of the output, Vout for two circuit above. Given the transformer to have a 12 V rms secondary voltage for the standard 120 V across the primary. Examine the peak output voltage for the Bridge rectifier with the practical model, and calculate the Peak Inverse Voltage (PIV) required for the diodes. +5 V- +100 V V. 0 V. 0 IN4001 IN4003 -5 V--- -100 V--- 1Okf 1.0k Figure 5
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Step 1

DIODE:

A diode is a semiconductor device that functions as a current one-way switch. It lets current flow freely in one direction while drastically restricting current flow in the other. Because they convert alternating current (ac) to pulsing direct current (dc), diodes are also known as rectifiers (dc). The type, voltage, and current capability of diodes are all rated. Anode (positive lead) and cathode (negative lead) define the polarity of a diode. When a positive voltage is supplied to the anode, most diodes enable current to flow.

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