Question 2: A Body at rest was accelerated, and it traveled for 5 minutes The constant acceleration provided to th body was 2 m/sec². Find the final velocity the object had before coming to a stop. Also, answer the equation of motion used
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Q: How much distance does he travel ?
A: Given data; Speed of men=20 ms-1Time taken by him=60 minFind distance does he travel ?
Q: d. 1 foot/nanosecond x -) ×(- _m/s (Note: “nano" is the metric prefix which is equivalent to 10-9.)
A: solution as
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A: we will use simple formula, Distance Travelled = Velocity × Time
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A: Velocity of a sky diver is given by the following function v(t) = 49(1 - e-0.19t)
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A: Speed is given by V = distance/time
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Q: we use meters “per” second when calculating speed?
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A: Given: The acceleration due to gravity on the moon is 1.6 m/s2. The time taken is 1.23 s.
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A: The average velocity between the time interval [1,3] is, v=x3-x1t3-t1v=71 feet-16 feet3 seconds-1…
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