i need the ans of both subparts i surely upvote u Investigation Il: What is your resistance?You have a resistance in your body, which means that current can flow through your body. Small currents aren't a bigdeal (in fact all the cells in your body create their own currents to move ions and many other things around), but bigcurrents can cause electrocution. In this procedure, you'll use the meters to measureyour own resistance and then see how that varies through different body parts whenthey are wet and dry. After that, you'll measure the resistance of some objects thatyou can find around your house. A video on moodle will help you set this up this ifyou're working at home.1. Use the meters to measure your internal resistance with dry hands. Place oneprobe in each hand as shown in the photo to the right, and record the smallestvalue that you measure in the table. Turn the dial to the 200OK setting in thesection labeled "Q" and then go down from there if you can to obtain the mostprecise reading possible. The red probe should be in the middle socket, blackprobe in the bottom socket, and top socket empty. (Figure 1)Figure 1: To measure the resistancebetween your hands, hold the two probeslike this.2. Have you ever heard that electricity and water don't mix? This is because water is anexcellent conductor. Measure how your internal resistance changes when you're inwater by sticking your fingers under water while they're holding the probes. (Figure 2)3.Not all body parts have the sameresistance. Find the resistance for a few morebody parts and write the results in the table.Pay close attention to how wet your skin isbecause wet skin has a much smaller resistancethan dry skin. Note: you'll likely observe that it's Figure 3: To measure thethe wetness of your skin, and not the distancebetween the body parts, that matters most.Inside, your body is mostly water so it is anexcellent conductor with very little resistance. (Figure 3).resistance under water, dipyour hands in water whilethey're holding the probes.Figure 2: On the left, my dry skin measuresI've reminded you several timesthis semester that when you use themeters you should be careful not totouch both of the probes becauseyou'll be hooking yourself up parallel with the circuit. Let's test how much4.>2000k2 On the right, a thick layer of lotion085moistened my skin, and now the resistance is443k2this matters by measuring the resistance the three resistors in this lab whenyou are touching both sides of the probe. (Figure 4)5. Find a few common household objects and measure their resistance. Recordthose values in the table below. Try to make sure you get a good mix ofinsulators and conductors. You will likely need to use a variety of differentsettings – if the resistance is small, use the 2000 2 or 200 2 settings. If theFigure 4: This is how NOT to use a meter. I'mnumber is large, use the 20k S, 200k 2, or 2000k 2 settings. If the meterrecords "1" on the 2000K setting, then this means that the resistance is>2000k2 (this will happen if you are measuring an insulator).touching both probes, so I am hooked up inparallel with this resistor. The reading I see is85kkfor this 100k2 resistor - a huge error!Question 2-1: Why did the resistance between your two hands get smaller when they were wet?Question 2-2: Conductors are objects that have a small resistance to the flow of charge, which means they can easilysupport a current. What types of household objects were conductors? Insulators?

As per the honour code I will answer only the first question.Kindly repost the other questions…

Answered: Question 2-1: Why did the resistance…

Question 2-1: Why did the resistance between your two hands get smaller when they were wet?

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

Similar questions

If open-loop gain is divided by two, then gain crossover frequency will a. Becomes half b. not affected c. Gets doubled O d. Becomes one-fourth
Answer what is asked. ASAP
Q) In the positive feedback the closed loop gain is Af = A/(1+Aß) O (b) Af = A (1+Aß) O %3D (c) Af = A/(1-Aß) O (d) Af = A (1-Aß) O
Pls help thank you i'll rate
Determine the OPAMP parameters
How many negative feedback loops in the following closed-loop system? H: 14 - O A) Five O B) Two C) One O D) Three E) Four
Urgent
2/Mention an application an the topic f oP timization ?
Please show work
The following open-loop systems are to be digitally feedback-controlled. Select a suitable sampling period for each if the closed-loop system is to be designed for the given specifications. 1. G(s) 2. G(s) = = s+3 1 s²+7s+25 sensor delay=0.025s ,sensor delay=0.03s "
How the integrator operate?
please answer clearly and fast