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Question 1 Which sorting algorithm is implemented here? Question 2 What is the time complexity of this sort in the worst case? Question 3 Have a look at the array below. We are trying to do quicksort on this array to sort it in ascending order. We wrote an algorithm that always takes the middle element as pivot. How the array will look like after first iteration(write in this format: 11,12,13,14,15) Array: 812 734 689 155 667 368 964 831 167 .

Question 1 Which sorting algorithm is implemented here? Question 2 What is the time complexity of this sort in the worst case? Question 3 Have a look at the array below. We are trying to do quicksort on this array to sort it in ascending order. We wrote an algorithm that always takes the middle element as pivot. How the array will look like after first iteration(write in this format: 11,12,13,14,15) Array: 812 734 689 155 667 368 964 831 167 .

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question 1 Which sorting algorithm is implemented here?

Question 2 What is the time complexity of this sort in the worst case?

Question 3 Have a look at the array below. We are trying to do quicksort on this array to sort it in ascending order. We wrote an algorithm that always takes the middle element as pivot. How the array will look like after first iteration(write in this format: 11,12,13,14,15) Array: 812 734 689 155 667 368 964 831 167 .

You are given a code below: def Sort(arr): if length(arr) > 1: a = length(arr)//2 1 = arr[:a] r - arr[a:] Sort(1) Sort(r) b = c = d = 0 while b < length(1) and c < length(r): if 1[b] < r[c]: arr[d] = 1[b] b += 1 else: arr[d] = r[c] C += 1 d += 1 while b < length(1): arr[d] = 1[b] b += 1 d += 1 while c < length(r): arr[d] = r[c] C += 1 d += 1 def printList(arr): for i in range(length(arr)): print(arr[i], end=" ") print()
Transcribed Image Text:You are given a code below: def Sort(arr): if length(arr) > 1: a = length(arr)//2 1 = arr[:a] r - arr[a:] Sort(1) Sort(r) b = c = d = 0 while b < length(1) and c < length(r): if 1[b] < r[c]: arr[d] = 1[b] b += 1 else: arr[d] = r[c] C += 1 d += 1 while b < length(1): arr[d] = 1[b] b += 1 d += 1 while c < length(r): arr[d] = r[c] C += 1 d += 1 def printList(arr): for i in range(length(arr)): print(arr[i], end=" ") print()
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