(Question 19 and 23) show all work, thank you! #19 answer given= 2.78m #23 answer given = 20; 25

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(Question 19 and 23) show all work, thank you!

#19 answer given= 2.78m

#23 answer given = 20; 25

17-22. Approximating displacement The velocity of an object is given by the
following functions on a specified interval. Approximate the displacement of the
object on this interval by subdividing the interval into n subintervals. Use the left
endpoint of each subirlterval to compute the height of the rectangles.
17.v2t +1 (m/s), for 0 ≤ t ≤ 8; n = 2
18. TV et (m/s), for 0 < t < 3; n = 3
=
1
(m/s), for 0 < t < 8; n = 4
19. V =
20. V =
21. τ υ
22. V =
2t + 1
t²
+4 (ft/s), for 0 ≤ t≤ 12; n = 6
2
= 4√t+1(mi/hr), for 0 ≤ t ≤ 15; n = 5
t + 3
(m/s), for 0 < t < 4; n = 4.
6
Transcribed Image Text:17-22. Approximating displacement The velocity of an object is given by the following functions on a specified interval. Approximate the displacement of the object on this interval by subdividing the interval into n subintervals. Use the left endpoint of each subirlterval to compute the height of the rectangles. 17.v2t +1 (m/s), for 0 ≤ t ≤ 8; n = 2 18. TV et (m/s), for 0 < t < 3; n = 3 = 1 (m/s), for 0 < t < 8; n = 4 19. V = 20. V = 21. τ υ 22. V = 2t + 1 t² +4 (ft/s), for 0 ≤ t≤ 12; n = 6 2 = 4√t+1(mi/hr), for 0 ≤ t ≤ 15; n = 5 t + 3 (m/s), for 0 < t < 4; n = 4. 6
23-24. Left and right Riemann sums Use the figures to calculate the left and
right Riemann sums for f on the given interval and for the given value of n.
23. f(x) = x + 1 on [1, 6]; n = 5
YA
YA
7
6
5
4
3-
2-
1
0
1
2
f(x) = x + 1
3
4
5 6 X
7
6
5.
4
3
2
1
0
1
2
f(x) = x + 1
3
4
5 6
X
Transcribed Image Text:23-24. Left and right Riemann sums Use the figures to calculate the left and right Riemann sums for f on the given interval and for the given value of n. 23. f(x) = x + 1 on [1, 6]; n = 5 YA YA 7 6 5 4 3- 2- 1 0 1 2 f(x) = x + 1 3 4 5 6 X 7 6 5. 4 3 2 1 0 1 2 f(x) = x + 1 3 4 5 6 X
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