QUESTION 18 Test the significance of the constion coefficient at -0.05. Use the P-value method. An environmentalist wants to determine the relationships between the numbers (in thousands) of forest fires over the year amd the mumber (in hundred thousands) of acres burned. The data for 8 recent years are shown. Describe the relationship. Number of fires x Number of acres burned y 73 90 59 48 83 61 57 46 62 43 20 26 49 15 30 16 Ot-2.600 so 0.02 < P-value <0.05. Therefore the P-value <0.05 so we reject the mull hypothesis. Ot=0.928 so 0.10< P-value <0.20. Therefore the P-value > 0.05 so we reject the null hypothesis. Pt%32.600 so 0.02 < P-value <0.05. Therefore the P-value <0.05 so we do not reject the mull hypothesis. t 0.928 so 0.10 < P-value <0.20. Therefore the P-value> 0.05 so we do not reject the null hypothesis.

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QUESTION Ta
Test the significance of the con.stion coefficient at 0-0.05, Use the Pevalue method.
An environmentalist wants to determine the relationships between the numbers (in thousands) of forest fires over the year nd
the mumber (in hundred thousands) of acres burned. The data for 8 recent years are shown. Describe the relationship.
Number of fires x
Number of acres
burned y
73
90
59
48
83
61
57
46
62
43
20
26
49
15
30
16
Ot%=2.600 so 0.02 < P-value <0.05. Therefore the P-value <0.05 so we reject the mull hypothesis.
Ot= 0.928 so 0.10<P-value <0.20. Therefore the P-value > 0.05 so we reject the null hypothesis.
Ot= 2.600 so 0.02 < P-value <0.05. Therefore the P-value <0.05 so we do not reject the null hypothesis.
Ot=0.928 so 0.10 < P-value <0.20. Therefore the P-value > 0.05 so wve do not reject the null hypothesis.
Transcribed Image Text:QUESTION Ta Test the significance of the con.stion coefficient at 0-0.05, Use the Pevalue method. An environmentalist wants to determine the relationships between the numbers (in thousands) of forest fires over the year nd the mumber (in hundred thousands) of acres burned. The data for 8 recent years are shown. Describe the relationship. Number of fires x Number of acres burned y 73 90 59 48 83 61 57 46 62 43 20 26 49 15 30 16 Ot%=2.600 so 0.02 < P-value <0.05. Therefore the P-value <0.05 so we reject the mull hypothesis. Ot= 0.928 so 0.10<P-value <0.20. Therefore the P-value > 0.05 so we reject the null hypothesis. Ot= 2.600 so 0.02 < P-value <0.05. Therefore the P-value <0.05 so we do not reject the null hypothesis. Ot=0.928 so 0.10 < P-value <0.20. Therefore the P-value > 0.05 so wve do not reject the null hypothesis.
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