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Question 17 :S- Given : 4x - 3 A = √ (21²+8) √u²+2 ® / / / 1 (2011 B (2u²+11)u √u²+2 © ²/2 √ ( 2 u ² + 11) √u²+2 1 (2u²+8) u 8x + 1 dx. If we let the substitution "=√4x-5, the resulting integral becomes -du du -du du

Question 17 :S- Given : 4x - 3 A = √ (21²+8) √u²+2 ® / / / 1 (2011 B (2u²+11)u √u²+2 © ²/2 √ ( 2 u ² + 11) √u²+2 1 (2u²+8) u 8x + 1 dx. If we let the substitution "=√4x-5, the resulting integral becomes -du du -du du

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question 17 :S- Given : 4x - 3 A = √ (21²+8) √u²+2 ® / / / 1 (2011 B (2u²+11)u √u²+2 © 1-S (24² +11) du √u²+2 Ⓒ = √ ( 2u² + 8) u Ⓒ(24²+8) √√u²+2 8x + 1 dx. If we let the substitution "=√4x-5, the resulting integral becomes -du du du
Transcribed Image Text:Question 17 :S- Given : 4x - 3 A = √ (21²+8) √u²+2 ® / / / 1 (2011 B (2u²+11)u √u²+2 © 1-S (24² +11) du √u²+2 Ⓒ = √ ( 2u² + 8) u Ⓒ(24²+8) √√u²+2 8x + 1 dx. If we let the substitution "=√4x-5, the resulting integral becomes -du du du
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