Question 17 of 32 10 0OL of propane

Chemistry
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Chapter1: Chemical Foundations
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"What is the mass (in grams) of 10.00 L of propane vapor (C₃H₈) at STP?"

This question explores the concept of calculating the mass of a gas under standard temperature and pressure (STP) conditions. 

- **STP Conditions**: Standard temperature and pressure are defined as 0°C (273.15 K) and 1 atmosphere pressure. Under these conditions, one mole of any ideal gas occupies 22.4 liters.
  
- **Propane (C₃H₈)**: To find the mass of 10.00 L of propane vapor, the molar mass of propane needs to be calculated. The molecular formula indicates 3 carbon atoms and 8 hydrogen atoms.

- **Calculation Steps**:
  1. **Find Molar Mass of Propane**:
     - Carbon: 12.01 g/mol × 3 = 36.03 g/mol
     - Hydrogen: 1.01 g/mol × 8 = 8.08 g/mol
     - Total molar mass of C₃H₈ = 36.03 + 8.08 = 44.11 g/mol
  
  2. **Use Ideal Gas Law at STP Conditions**:
     - 1 mole of gas at STP = 22.4 L
     - Determine moles of propane in 10.00 L:
       \[
       \text{Moles of C₃H₈} = \frac{10.00 L}{22.4 L/mol} ≈ 0.446 moles
       \]

  3. **Calculate Mass**:
     - Mass = Moles × Molar Mass
     - Mass = 0.446 moles × 44.11 g/mol ≈ 19.67 grams

Thus, at STP, 10.00 liters of propane vapor has a mass of approximately 19.67 grams.
Transcribed Image Text:The image presents a question for educational purposes: "What is the mass (in grams) of 10.00 L of propane vapor (C₃H₈) at STP?" This question explores the concept of calculating the mass of a gas under standard temperature and pressure (STP) conditions. - **STP Conditions**: Standard temperature and pressure are defined as 0°C (273.15 K) and 1 atmosphere pressure. Under these conditions, one mole of any ideal gas occupies 22.4 liters. - **Propane (C₃H₈)**: To find the mass of 10.00 L of propane vapor, the molar mass of propane needs to be calculated. The molecular formula indicates 3 carbon atoms and 8 hydrogen atoms. - **Calculation Steps**: 1. **Find Molar Mass of Propane**: - Carbon: 12.01 g/mol × 3 = 36.03 g/mol - Hydrogen: 1.01 g/mol × 8 = 8.08 g/mol - Total molar mass of C₃H₈ = 36.03 + 8.08 = 44.11 g/mol 2. **Use Ideal Gas Law at STP Conditions**: - 1 mole of gas at STP = 22.4 L - Determine moles of propane in 10.00 L: \[ \text{Moles of C₃H₈} = \frac{10.00 L}{22.4 L/mol} ≈ 0.446 moles \] 3. **Calculate Mass**: - Mass = Moles × Molar Mass - Mass = 0.446 moles × 44.11 g/mol ≈ 19.67 grams Thus, at STP, 10.00 liters of propane vapor has a mass of approximately 19.67 grams.
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