QUESTION 17 Let's suppose someone flips a fair coin three times. 1. How many outcomes are possible? 2. What is the probability of getting exactly one tail? Give as a fraction 3. What is the probability of getting at most two tails? Give asa fraction
QUESTION 17 Let's suppose someone flips a fair coin three times. 1. How many outcomes are possible? 2. What is the probability of getting exactly one tail? Give as a fraction 3. What is the probability of getting at most two tails? Give asa fraction
College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section: Chapter Questions
Problem 2P: Family Planning A intend to have two children. What is tie probability that they will have child of...
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![### Probability Questions for Educational Practice
#### Coin Flipping Probability
**Question 17:**
Let's suppose someone flips a fair coin three times.
1. **How many outcomes are possible?**
- There are 2 outcomes for each coin flip (Heads or Tails). Therefore, flipping a coin three times results in \(2^3 = 8\) possible outcomes.
2. **What is the probability of getting exactly one tail? Give as a fraction.**
- The possible outcomes with exactly one tail are: HTT, THT, TTH. There are 3 such outcomes. Since there are 8 possible outcomes in total, the probability is \(\frac{3}{8}\).
3. **What is the probability of getting at most two tails? Give as a fraction.**
- Getting at most two tails means getting 0, 1, or 2 tails. The possible outcomes are HHH, HHT, HTH, THH, HTT, THT, TTH. There are 7 favorable outcomes. The probability is \(\frac{7}{8}\).
#### Dice Rolling Probability
**Question 18:**
Consider the following experiment: roll a pair of fair dice and observe the sample space. Answer the following questions based on the above sample space.
1. **What is the probability of obtaining a total score (sum of the faces of both dice) of 11?**
- The possible outcomes with a total score of 11 are (5,6) and (6,5), which are 2 favorable outcomes. Since there are 36 possible outcomes when rolling a pair of dice (6 sides each, so \(6 \times 6 = 36\)), the probability is \(\frac{2}{36} = \frac{1}{18}\).
2. **What is the probability of obtaining a total score of 9?**
- The possible outcomes with a total score of 9 are (3,6), (4,5), (5,4), and (6,3), which are 4 favorable outcomes. Therefore, the probability is \(\frac{4}{36} = \frac{1}{9}\).
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Transcribed Image Text:### Probability Questions for Educational Practice
#### Coin Flipping Probability
**Question 17:**
Let's suppose someone flips a fair coin three times.
1. **How many outcomes are possible?**
- There are 2 outcomes for each coin flip (Heads or Tails). Therefore, flipping a coin three times results in \(2^3 = 8\) possible outcomes.
2. **What is the probability of getting exactly one tail? Give as a fraction.**
- The possible outcomes with exactly one tail are: HTT, THT, TTH. There are 3 such outcomes. Since there are 8 possible outcomes in total, the probability is \(\frac{3}{8}\).
3. **What is the probability of getting at most two tails? Give as a fraction.**
- Getting at most two tails means getting 0, 1, or 2 tails. The possible outcomes are HHH, HHT, HTH, THH, HTT, THT, TTH. There are 7 favorable outcomes. The probability is \(\frac{7}{8}\).
#### Dice Rolling Probability
**Question 18:**
Consider the following experiment: roll a pair of fair dice and observe the sample space. Answer the following questions based on the above sample space.
1. **What is the probability of obtaining a total score (sum of the faces of both dice) of 11?**
- The possible outcomes with a total score of 11 are (5,6) and (6,5), which are 2 favorable outcomes. Since there are 36 possible outcomes when rolling a pair of dice (6 sides each, so \(6 \times 6 = 36\)), the probability is \(\frac{2}{36} = \frac{1}{18}\).
2. **What is the probability of obtaining a total score of 9?**
- The possible outcomes with a total score of 9 are (3,6), (4,5), (5,4), and (6,3), which are 4 favorable outcomes. Therefore, the probability is \(\frac{4}{36} = \frac{1}{9}\).
**Instructions:**
Click "Save and Submit" to save and submit your answers. Click "Save All Answers" to save all answers.
### Weather Information:
- 74°F
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