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Question 16 Let U = {6, a, 8} and A, B and C be subsets of U. The set (B − C) = (An (B~ C')) is NOT an identity. Which one of the following alternatives contains sets A, B and C that can be used as counterexample to prove that the set (B − C) = (A ~ (BC')) is not an identity. 1. A = {6}, B = {6}, C = {a, 8} 2. A = {6, a}, B = {}, C = {6, a} 3. A = {8}, B = {6, 8}, C = {a} 4. A = {a, 8}, B = {}, C = {a}

Question 16 Let U = {6, a, 8} and A, B and C be subsets of U. The set (B − C) = (An (B~ C')) is NOT an identity. Which one of the following alternatives contains sets A, B and C that can be used as counterexample to prove that the set (B − C) = (A ~ (BC')) is not an identity. 1. A = {6}, B = {6}, C = {a, 8} 2. A = {6, a}, B = {}, C = {6, a} 3. A = {8}, B = {6, 8}, C = {a} 4. A = {a, 8}, B = {}, C = {a}

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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QUESTION 16

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Question 16 Let U = {6, a, 8} and A, B and C be subsets of U. The set (B − C) = (A ~ (B ~ C')) is NOT an identity. Which one of the following alternatives contains sets A, B and C that can be used as counterexample to prove that the set (B − C) = (A ~ (B~ C')) is not an identity. 1. A = {6}, B = {6}, C = {a, 8} 2. A = {6, a}, B = {}, C = {6, a} 3. A = {8}, B = {6, 8}, C = {a} 4. A = {a, 8}, B = { }, C = {a}
Transcribed Image Text:Question 16 Let U = {6, a, 8} and A, B and C be subsets of U. The set (B − C) = (A ~ (B ~ C')) is NOT an identity. Which one of the following alternatives contains sets A, B and C that can be used as counterexample to prove that the set (B − C) = (A ~ (B~ C')) is not an identity. 1. A = {6}, B = {6}, C = {a, 8} 2. A = {6, a}, B = {}, C = {6, a} 3. A = {8}, B = {6, 8}, C = {a} 4. A = {a, 8}, B = { }, C = {a}
Expert Solution
Step 1

The intersection of two sets means the set contains common elements of both sets.

Subtraction of two sets is the set of all the elements that are in the first set not in the second set.

The complement of a set is the set of elements that has all the elements except the element of the given set. 

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