Question 15 of 15 An electromagnetic wave with frequency f = 2 x 1010 Hz is traveling in a transparent material having an index of refraction n = 1.5. What is the wavelength of the wave? 2.0 cm 1.0 cm 2.3 cm 1.5 cm 3.0 cm

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Chapter1: Units, Trigonometry. And Vectors
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**Question 15 of 15**

An electromagnetic wave with frequency \( f = 2 \times 10^{10} \) Hz is traveling in a transparent material having an index of refraction \( n = 1.5 \). What is the wavelength of the wave?

**Options:**
- 2.0 cm
- 1.0 cm
- 2.3 cm
- 1.5 cm
- 3.0 cm

There are no graphs or diagrams present in this image. This question appears to test understanding of the relationship between wave frequency, speed, and wavelength in a medium with a given index of refraction. To find the wavelength, use the formula:

\[ \lambda = \frac{v}{f} \]

where \( v \) is the speed of light in the given medium and \( f \) is the frequency of the wave. Given that the speed of light \( c \) in vacuum is \( 3 \times 10^8 \) m/s, the speed of light in the material will be:

\[ v = \frac{c}{n} = \frac{3 \times 10^8 \text{ m/s}}{1.5} = 2 \times 10^8 \text{ m/s} \]

Substituting the given frequency:

\[ \lambda = \frac{2 \times 10^8 \text{ m/s}}{2 \times 10^{10} \text{ Hz}} = 0.01 \text{ m} = 1 \text{ cm} \]

Therefore, the correct answer is:

- 1.0 cm
Transcribed Image Text:**Question 15 of 15** An electromagnetic wave with frequency \( f = 2 \times 10^{10} \) Hz is traveling in a transparent material having an index of refraction \( n = 1.5 \). What is the wavelength of the wave? **Options:** - 2.0 cm - 1.0 cm - 2.3 cm - 1.5 cm - 3.0 cm There are no graphs or diagrams present in this image. This question appears to test understanding of the relationship between wave frequency, speed, and wavelength in a medium with a given index of refraction. To find the wavelength, use the formula: \[ \lambda = \frac{v}{f} \] where \( v \) is the speed of light in the given medium and \( f \) is the frequency of the wave. Given that the speed of light \( c \) in vacuum is \( 3 \times 10^8 \) m/s, the speed of light in the material will be: \[ v = \frac{c}{n} = \frac{3 \times 10^8 \text{ m/s}}{1.5} = 2 \times 10^8 \text{ m/s} \] Substituting the given frequency: \[ \lambda = \frac{2 \times 10^8 \text{ m/s}}{2 \times 10^{10} \text{ Hz}} = 0.01 \text{ m} = 1 \text{ cm} \] Therefore, the correct answer is: - 1.0 cm
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