Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
Question 14 please
![• Question 14: What alkyl halides are formed when each ether is treated with
HBr?
a. CH,CH2-O-CH,CH3 b. (CH3),CH-O-CH,CH
a.
• Question 15: Draw the product of each reaction, indicating the stereochemistry
at any stereogenic centers.
CH3
[1] CH,CH,O
[2] H₂O
b.
CH₂
C.
H
-O-CH3
GH
H
[1] H-C=C-
[2] H₂O](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4ddf1583-af9c-4cdb-b832-89f0a6e45ec4%2F0376b180-d9ed-43f8-a44f-f483039d0ab2%2F8mv2wbw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:• Question 14: What alkyl halides are formed when each ether is treated with
HBr?
a. CH,CH2-O-CH,CH3 b. (CH3),CH-O-CH,CH
a.
• Question 15: Draw the product of each reaction, indicating the stereochemistry
at any stereogenic centers.
CH3
[1] CH,CH,O
[2] H₂O
b.
CH₂
C.
H
-O-CH3
GH
H
[1] H-C=C-
[2] H₂O
Expert Solution
Step 1
The given compounds are ether, so when an ether react with HBr , an alcohol and an alkyl Bromide.
First H+ is added from HBr on Oxygen , then alcohol group leaves to generate a carbocation. So alkyl halide is formed corresponding to most stable carbocation.
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