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QUESTION 14 The cross section of excavation is: O 7.40 m2 O 4.06 m2 3.58 m2 O None of the answers are correct QUESTION 15 The exterior perimeter of foundation wall is: O 108.00 m 101.00 m 95.00 m O None of the answers are correct QUESTION 16 The PCL of foundation wall is: O 104.45 m 83.80 m O 100.00 m

QUESTION 14 The cross section of excavation is: O 7.40 m2 O 4.06 m2 3.58 m2 O None of the answers are correct QUESTION 15 The exterior perimeter of foundation wall is: O 108.00 m 101.00 m 95.00 m O None of the answers are correct QUESTION 16 The PCL of foundation wall is: O 104.45 m 83.80 m O 100.00 m

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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12500 4 250 - 1100 250 38000 SECTION AI 550 SECTION A 1. FOUNDATION PLAN CIVL 2063 PROJECT NO. SCALE NTS DRAWING NO. B-1 2. SECTION A-A ESTIMATING CIVIL PROJECTS
Transcribed Image Text:12500 4 250 - 1100 250 38000 SECTION AI 550 SECTION A 1. FOUNDATION PLAN CIVL 2063 PROJECT NO. SCALE NTS DRAWING NO. B-1 2. SECTION A-A ESTIMATING CIVIL PROJECTS
QUESTION 14 The cross section of excavation is: O 7.40 m2 4.06 m2 O 3.58 m2 None of the answers are correct QUESTION 15 The exterior perimeter of foundation wall is: O 108.00 m O 101.00 m 95.00 m O None of the answers are correct QUESTION 16 The PCL of foundation wall is: O 104.45 m 83.80 m O 100.00 m
Transcribed Image Text:QUESTION 14 The cross section of excavation is: O 7.40 m2 4.06 m2 O 3.58 m2 None of the answers are correct QUESTION 15 The exterior perimeter of foundation wall is: O 108.00 m O 101.00 m 95.00 m O None of the answers are correct QUESTION 16 The PCL of foundation wall is: O 104.45 m 83.80 m O 100.00 m
Expert Solution
Step 1

Question 14

Cross-section of the excavation = 550 x (250+1100) = 0.55 x (.25+1.1) =0.55 x 1.35 = 0.7425 m2 

Question 15

The exterior perimeter of the foundation wall = 38 x 2 + 12.5 x 2 = 101 m

Question 16

PCL of the foundation wall = (38 - 0.25) x 2 + (12.5 - 0.25) x 2 = 100 m

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