Question 14 Given the following pseudocode for a semaphore monitor. monitor Semaphore { int s = 0; ## s >= 0 cond semQ; # signaled when s > 0 procedure Down() { } while (s == 0) wait(semQ); S = S-1; procedure Up() { S = s+1; signal(semQ); } ... // more statements here } The proposed code does not work correctly with signal-and-wait discipline. True: when the signaler continues, the signaled process can also enter so both processes will be inside the monitor at the same time. True: the signaler and the signaled can deadlock. ● False: it works fine with signal-and-wait. True: when the signaled process is awake, it doesn't check the condition again so race can occur. True: when the signaler suspends itself, another thread waiting at the entry queue can enter while the signaled thread is inside the monitor.
Question 14 Given the following pseudocode for a semaphore monitor. monitor Semaphore { int s = 0; ## s >= 0 cond semQ; # signaled when s > 0 procedure Down() { } while (s == 0) wait(semQ); S = S-1; procedure Up() { S = s+1; signal(semQ); } ... // more statements here } The proposed code does not work correctly with signal-and-wait discipline. True: when the signaler continues, the signaled process can also enter so both processes will be inside the monitor at the same time. True: the signaler and the signaled can deadlock. ● False: it works fine with signal-and-wait. True: when the signaled process is awake, it doesn't check the condition again so race can occur. True: when the signaler suspends itself, another thread waiting at the entry queue can enter while the signaled thread is inside the monitor.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Transcribed Image Text:Question 14
Given the following pseudocode for a semaphore monitor.
monitor Semaphore {
int s = 0; ## s >= 0
cond semQ; # signaled when s > 0
procedure Down() {
}
while (s == 0) wait(semQ);
s = s-1;
procedure Up() {
S = s+1;
signal(semQ);
}
***
... // more statements here
}
The proposed code does not work correctly with signal-and-wait discipline.
True: when the signaler continues, the signaled process can also enter so both
processes will be inside the monitor at the same time.
True: the signaler and the signaled can deadlock.
False: it works fine with signal-and-wait.
True: when the signaled process is awake, it doesn't check the condition again so race
can occur.
True: when the signaler suspends itself, another thread waiting at the entry queue
can enter while the signaled thread is inside the monitor.
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