**Question 13 of 31****Problem Statement:**Calculate how many atoms of carbon are produced by the complete reaction of 7.09 grams of magnesium turnings with excess dry ice (CO₂) according to the balanced chemical reaction:\[ 2 \text{Mg}(s) + \text{CO}_2(g) \rightarrow 2 \text{MgO}(s) + \text{C}(s) \]**Solution Details:**1. **Conversion Setup:** - Use the molar mass of Mg to convert grams of magnesium to moles. - Utilize the stoichiometric ratio from the balanced equation to relate moles of Mg to moles of C. - Convert moles of C to atoms using Avogadro’s number.2. **Step-by-Step Calculation:** - Convert grams of magnesium to moles of magnesium: \[ \frac{1 \text{ mol Mg}}{24.31 \text{ g Mg}} \] - Use the stoichiometric ratio between Mg and C from the balanced equation: \[ \frac{1 \text{ mol C}}{2 \text{ mol Mg}} \] - Convert moles of carbon to atoms using Avogadro’s number: \[ 6.022 \times 10^{23} \text{ atoms Mg} \] - The calculated number of atoms of carbon: \[ 3.56 \times 10^{23} \text{ atoms C} \]3. **Diagrams:** There is a visual step-by-step layout of each conversion and calculation, detailing the process from grams of magnesium to moles of magnesium, from moles of magnesium to moles of carbon, and finally, from moles of carbon to atoms of carbon.**Answer:**The complete reaction of 7.09 grams of magnesium will produce approximately \(3.56 \times 10^{23}\) atoms of carbon.**Additional Tools:**- The interface allows adding, deleting, and resetting factors for calculations.- Options for inputting values related to atoms, moles, and grams for various substances are provided.

Answered: Image /qna-images/answer/03b6207e-4238-49f0-8074-f463596c4634.jpg

Question 13 of 31 How many atoms of carbon are produced by the complete reaction of 7.09 grams of magnesium turnings with excess dry ice (CO2), according to the balanced chemical reaction: 2 Mg(s) +CO2(s) 2 MgO(s) + C(s) 1 motMg 1 metC 6.022 x 102 atoms Mg = 3.56 x 1023 atoms C 24.31 2 motMg metC mol C 6.022 x 1023 atoms Mg = 3.56 x 1023 atoms C mol Mg 1 mol C ADD FACTOR DELETE ANSWER RESET 7.09 1.75 3.56 x 1023 3.50 40.30 1 8.78 x 1022 0.146 1.76 x 1023 44.01 0.292 12.01 2 24.31 6.022 x 1023 mol Mg g CO2 mol C atoms CO2 g Mg mol CO2 g Mgo atoms MgO mol Mgo atoms Mg atoms C

Question 13 of 31 How many atoms of carbon are produced by the complete reaction of 7.09 grams of magnesium turnings with excess dry ice (CO2), according to the balanced chemical reaction: 2 Mg(s) +CO2(s) 2 MgO(s) + C(s) 1 motMg 1 metC 6.022 x 102 atoms Mg = 3.56 x 1023 atoms C 24.31 2 motMg metC mol C 6.022 x 1023 atoms Mg = 3.56 x 1023 atoms C mol Mg 1 mol C ADD FACTOR DELETE ANSWER RESET 7.09 1.75 3.56 x 1023 3.50 40.30 1 8.78 x 1022 0.146 1.76 x 1023 44.01 0.292 12.01 2 24.31 6.022 x 1023 mol Mg g CO2 mol C atoms CO2 g Mg mol CO2 g Mgo atoms MgO mol Mgo atoms Mg atoms C

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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