Question 12 Give the equilibrium constant expression for the reaction 2HBr₂(g) Br₂(g) + H₂(g) OK= [Brz] [H₂] / [HBr] OK= [Br2] [H₂]/[HBr]2 OK= [HBr]2/[Br₂][H₂] O Kc = 2[HBr]2/(2[Br₂]² x 2[H₂12) OK (Br₂]2 [H₂]²/[HBr] =
Question 12 Give the equilibrium constant expression for the reaction 2HBr₂(g) Br₂(g) + H₂(g) OK= [Brz] [H₂] / [HBr] OK= [Br2] [H₂]/[HBr]2 OK= [HBr]2/[Br₂][H₂] O Kc = 2[HBr]2/(2[Br₂]² x 2[H₂12) OK (Br₂]2 [H₂]²/[HBr] =
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![kJ/mol
+410 kJ/mol
LLEGES
20
O-410 kJ/mol
Question 12
Give the equilibrium constant expression for the reaction
2HBr2(g) Br₂(g) + H₂(g)
OK= [Br2] [H₂] / [HBr]
OK= [Br₂] [H₂]/[HBr]
OK [HBr]2/[Brz][H₂]
OK-2[HBr]2/(2[Br₂] x 2[H₂1)
OK [Br2] [H₂]²/[HBr]
121666
3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F9803650d-70c7-4129-9dcb-f0d0e3cb6614%2Fc65d288f-2b28-488a-95bc-7eedfd626e63%2Fbt84c8d_processed.jpeg&w=3840&q=75)
Transcribed Image Text:kJ/mol
+410 kJ/mol
LLEGES
20
O-410 kJ/mol
Question 12
Give the equilibrium constant expression for the reaction
2HBr2(g) Br₂(g) + H₂(g)
OK= [Br2] [H₂] / [HBr]
OK= [Br₂] [H₂]/[HBr]
OK [HBr]2/[Brz][H₂]
OK-2[HBr]2/(2[Br₂] x 2[H₂1)
OK [Br2] [H₂]²/[HBr]
121666
3
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