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Question 12 For the circuit shown, what is the Mesh Current Method equation for mesh A? j5 0 2Ω IA A) 62 - 45° V ーj10 j4 N A5430° V 3Ω 220° V IB OIA = 62 45° O (2 + j5)IA - (-j)(IA – IB)+ (6/135°) = 0 | O IA = 62135° O (2 + j5)IA + (-j)(Ia – IB) + (62 – 45°) = 0 %3D

Question 12 For the circuit shown, what is the Mesh Current Method equation for mesh A? j5 0 2Ω IA A) 62 - 45° V ーj10 j4 N A5430° V 3Ω 220° V IB OIA = 62 45° O (2 + j5)IA - (-j)(IA – IB)+ (6/135°) = 0 | O IA = 62135° O (2 + j5)IA + (-j)(Ia – IB) + (62 – 45°) = 0 %3D

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question 12 For the circuit shown, what is the Mesh Current Method equation for mesh A? j5 Ω 20 IA *) 62 - 45° V -j10 j4 N 40077 IB 5430° V 30 O IA = 6 45° O (2 + j5)IA - (-)(IA – IB) + (6/135°) = 0 O IA = 6Z135° O (2 + j5)IA + (-j)(Ia – IB) + (62 – 45°) = 0 Ouuti
Transcribed Image Text:Question 12 For the circuit shown, what is the Mesh Current Method equation for mesh A? j5 Ω 20 IA *) 62 - 45° V -j10 j4 N 40077 IB 5430° V 30 O IA = 6 45° O (2 + j5)IA - (-)(IA – IB) + (6/135°) = 0 O IA = 6Z135° O (2 + j5)IA + (-j)(Ia – IB) + (62 – 45°) = 0 Ouuti
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