Question 11 of 25Determine the number of moles in 4.21 x 10" molecules of Caci,STARTING AMOUNTADD FACTORANSWERRESET*()4.21 x 10 3.79 x 10" 0.6996.022 x 10"77.675.53110.986.99g Cacl, mol Caci. 9 CaCly/mol molecules CaCı.Question 13 of 25A 52-kg woman has 7.2 x 10mol of hemoglobin (molar mass = 64456 g/mol)in her blood. How many hemoglobin molecules is this?STARTINO AMOUNTADD FACTORANSWERRESET*( )7.2 x 101.1 x 10 6.022 x 10"1.2 x 10* 4.3 x 1064456460g hemoglobin molecules hemoglobin mol hemoglobing/molQuestion 19 of 25How many grams are in 1.66 × 1015 moleculesof CO?Question 23 of 25What is the mass in grams of 7.95 × 1015molecules of NO?

Given, Molecules of CaCl2= 4.21×1023 We have to find the no of mole of CaCl21 mole of CaCl2= 6.023×1023molecule 4.21×1023 molecule of CaCl2 = 4.21×1023/6.023×1023= 0.699mol Answer: 0.699mol

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Question 11 of Determine the number of moles in 4.21 x 10" molecules of Caci, STARTING AMOUNT ADO FACTOR ANSWER BESET *( ) 4.21 x 10 3.79 x 10 0699 776 6.022 x 10 75.53 110.98 6.99 g Caci, mol Cacl, a Cacimol molecules Caci,

Question 11 of Determine the number of moles in 4.21 x 10" molecules of Caci, STARTING AMOUNT ADO FACTOR ANSWER BESET *( ) 4.21 x 10 3.79 x 10 0699 776 6.022 x 10 75.53 110.98 6.99 g Caci, mol Cacl, a Cacimol molecules Caci,

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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