Question 11 of 15 A diffraction grating having 200 lines/mm is illuminated with light of wavelength λ. The m = 4 diffraction maximum is observed at an angle of 30°. What is λ? 625 nm 550 nm 400 nm 200 nm None of the above

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Chapter1: Units, Trigonometry. And Vectors
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### Question 11 of 15

A diffraction grating having 200 lines/mm is illuminated with light of wavelength λ. The m = 4 diffraction maximum is observed at an angle of 30°. What is λ?

- ⬤ 625 nm
- ⭘ 550 nm
- ⭘ 400 nm
- ⭘ 200 nm
- ⭘ None of the above

In this problem, a diffraction grating with 200 lines per millimeter is used, and we need to find the wavelength of the light (λ) based on the given conditions: the 4th-order diffraction maximum (m = 4) is seen at an angle of 30 degrees. The possible options for λ are provided in nanometers (nm).
Transcribed Image Text:### Question 11 of 15 A diffraction grating having 200 lines/mm is illuminated with light of wavelength λ. The m = 4 diffraction maximum is observed at an angle of 30°. What is λ? - ⬤ 625 nm - ⭘ 550 nm - ⭘ 400 nm - ⭘ 200 nm - ⭘ None of the above In this problem, a diffraction grating with 200 lines per millimeter is used, and we need to find the wavelength of the light (λ) based on the given conditions: the 4th-order diffraction maximum (m = 4) is seen at an angle of 30 degrees. The possible options for λ are provided in nanometers (nm).
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