Take Test: Homework 5-202220. Xbb.umflint.edu/webapps/assessment/take/launch.jsp?course_assessment_id=_442212 18tcourse_id%3_3645813_18tcontent_id%3D_8105239 18step3DnulY¥ Question Completion Status:O 1.75O -1.75-1.38O 1.821.03QUESTION 11Cholesterol. The American Heart Association reports that a total cholesterol score of 240 or higher represents high risk of heartdisease. A study of postmenopausal women reported a mean of 220 and standard deviation of 40. If the total cholesterol scoreshave a normal distribution, what proportion of the women fall in the high-risk category (e.g. cholesterol score of 240 or higher)?(4 points) Hint: you should draw a normal distribution curve and figure out what Z score corresponds to240 or higher to answer this question.

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Answered: QUESTION 11 Cholesterol. The American…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You are performing a study about weekly per capita milk consumption. A previous study found weekly per capita milk consumption to be normally distributed, with a mean of 43.9 fluid ounces and a standard deviation of 10.8 fluid ounces. You randomly sample 30 people and record the weekly milk consumptions shown below. 34, 53, 30, 37, 39, 45, 27, 62, 33, 45, 41, 24, 37, 53, 40, 39, 39, 45, 46, 45, 33, 30, 21, 39, 61, 41, 47, 39, 53, 34 a) Using seven classes, draw a frequency histogram to display these data. b) Find the mean of your sample. Find the standard deviation of your sample. c) Compare the mean and standard deviation of your sample with those of the previous study. Discuss the differences.
In this exercise, you will compare Chebyshev’s rule and the empirical rule. a. Compare the estimates given by the two rules for the percentage of observations that lie within two standard deviations to either side of the mean. Comment on the differences.b. Compare the estimates given by the two rules for the percentage of observations that lie within three standard deviations to either side of the mean. Comment on the differences.
The amount of money raised by Clayton State teams for the Statistics Games is normally distributed, with a mean of $360 and a standard deviation of $15. We want to determine what proportion of the teams raise less than $396. What is the z-score for the data value?
Lecture(10.9A): The Peabody Picture Vocabulary Test has a standard score population mean of 100 and a standard deviation of 15. You tested a class of Grade 2 students wondering if their scores are different from the population. After testing these hypothesis you grouped the children based on whether the oldest, middle, or youngest. Here is a summary of the grouped data. Oldest child: 87 ,84, 98, 104, 106, 91,96, 92, Middle child: 65, 74, 62, 60, 73, 64, 71,78 Youngest child: 115, 84, 85, 83, 95, 94, 108, 102, 89 Perform AVOVA post Ad Hoc (Bonfeirri correction) in Excell.
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"If the mean of a dataset is 50 and the standard deviation is 5, what is the z-score of the value 55? A. -1 B. O C. 1 D. 2"
The mean temperature in Amman for the month of October is 23 degrees with a standard deviation of 4.2 degrees. What is the z- score for a temperature of 29 degrees? O a. -1.43 O b. 1.43 O .0.71 O d. -0.95
We considered the differences between the temperature readings in January 1 of 1968 and 2008 at 51 locations in the continental US in Exercise 5.19. The mean and standard deviation of the reported differences are 1.1 degrees and 4.9 degrees respectively. see attachment
The scores on a standardized test are normally distributed with a mean of 100 and standard deviation of 25. What test score is 2.3 standard deviations above the mean? Submit Question
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Beth scored 88 on a nutrition test. The class mean was 81 and the standard deviation was 3.2. What is Beth's T-score? Group of answer choices 47.8 71.9 22.4 Beth's T-score cannot be calculated. Not enough information is provided.
Mary's height is 68 inches, in comparison to a group whose height is 65.5 inches with standard deviation of 1.5 inches. What is the z-score of Mary's height? What does the result tell you?

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