Question 10: Use the values in Table on the last page to determine AH° for the following reaction.

Chemistry
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**Some Bond Dissociation Energies, D**

| Bond         | D (kJ/mol) | Bond            | D (kJ/mol) | Bond            | D (kJ/mol) |
|--------------|------------|-----------------|------------|-----------------|------------|
| H−F          | 436        | (CH₃)₂C−I       | 209        | C₂H₅−CH₃        | 355        |
| H−Cl         | 432        | H₂C=CH−H        | 444        | (CH₃)₂C−CH₃     | 351        |
| H−Br         | 366        | H₂C=CH−Cl       | 368        | H₂C=CH−CH₃      | 396        |
| H−I          | 298        | H₂C−CH₂−CH₃     | 361        | H₂C−CH=CH₂      | 310        |
| Cl−Cl        | 243        | H₂C−CH₂−Cl      | 280        | -               | 611        |
| Br−Br        | 193        |                 |            | C₆H₅−H          | 464        |
| I−I          | 151        | C₆H₅−Cl         | 395        | C₆H₅−CH₃        | 427        |
| CH₃−H        | 435        | C₆H₅−CH₂−H      | 368        | -               | 332        |
| CH₃−CH₃      | 372        | C₆H₅−CH₂−Cl     | 293        | -               | 322        |
| CH₃−I        | 234        | C₆H₅−Br         | 337        | HO−H            | 498        |
| CH₃−NH₂      | 338        | C₆H₅−OH         | 460        | HO−OH           | 213        |
| C₂H₅−H       | 420        | H−C≡C−H         | 552        | C₆H₅−S−H        | 427        |
Transcribed Image Text:**Some Bond Dissociation Energies, D** | Bond | D (kJ/mol) | Bond | D (kJ/mol) | Bond | D (kJ/mol) | |--------------|------------|-----------------|------------|-----------------|------------| | H−F | 436 | (CH₃)₂C−I | 209 | C₂H₅−CH₃ | 355 | | H−Cl | 432 | H₂C=CH−H | 444 | (CH₃)₂C−CH₃ | 351 | | H−Br | 366 | H₂C=CH−Cl | 368 | H₂C=CH−CH₃ | 396 | | H−I | 298 | H₂C−CH₂−CH₃ | 361 | H₂C−CH=CH₂ | 310 | | Cl−Cl | 243 | H₂C−CH₂−Cl | 280 | - | 611 | | Br−Br | 193 | | | C₆H₅−H | 464 | | I−I | 151 | C₆H₅−Cl | 395 | C₆H₅−CH₃ | 427 | | CH₃−H | 435 | C₆H₅−CH₂−H | 368 | - | 332 | | CH₃−CH₃ | 372 | C₆H₅−CH₂−Cl | 293 | - | 322 | | CH₃−I | 234 | C₆H₅−Br | 337 | HO−H | 498 | | CH₃−NH₂ | 338 | C₆H₅−OH | 460 | HO−OH | 213 | | C₂H₅−H | 420 | H−C≡C−H | 552 | C₆H₅−S−H | 427 |
**Question 10:** Use the values in Table on the last page to determine ΔH° for the following reaction.

\[
\text{CH}_3\text{-C-Cl} + \text{HOH} \rightarrow \text{CH}_3\text{-C-OH} + \text{HCl}
\]

**Explanation:**

The image contains a chemical reaction involving the transformation of one molecule with a chlorine group to a molecule with a hydroxyl group. Specifically, the reaction is between a tertiary alkyl chloride (CH₃-C-Cl) and water (HOH), resulting in a tertiary alcohol (CH₃-C-OH) and hydrochloric acid (HCl). 

To solve for ΔH°, you need to look up the enthalpies of formation for each compound involved in this reaction from the table referenced on the last page and apply Hess's law:

\[
\Delta H° = \sum (\Delta H°_{\text{products}}) - \sum (\Delta H°_{\text{reactants}})
\]
Transcribed Image Text:**Question 10:** Use the values in Table on the last page to determine ΔH° for the following reaction. \[ \text{CH}_3\text{-C-Cl} + \text{HOH} \rightarrow \text{CH}_3\text{-C-OH} + \text{HCl} \] **Explanation:** The image contains a chemical reaction involving the transformation of one molecule with a chlorine group to a molecule with a hydroxyl group. Specifically, the reaction is between a tertiary alkyl chloride (CH₃-C-Cl) and water (HOH), resulting in a tertiary alcohol (CH₃-C-OH) and hydrochloric acid (HCl). To solve for ΔH°, you need to look up the enthalpies of formation for each compound involved in this reaction from the table referenced on the last page and apply Hess's law: \[ \Delta H° = \sum (\Delta H°_{\text{products}}) - \sum (\Delta H°_{\text{reactants}}) \]
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