Question 10 of 22 Macmillan Learning Consider the given reaction. :Br: ata :Br Which reactant is the Lewis acid and which is the Lewis base? Br₂ is the Lewis acid. FeBr is the Lewis acid. FeBr3 is the Lewis base. Br₂ is the Lewis base. :Br :Br: Fe Br :Br:

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**Question 10 of 22**

Consider the given reaction.

\[
\begin{array}{c}
\begin{array}{cc}
 & \cdot \cdot \cdot \cdot \dots \dfrac{\cdot \cdot \cdot \cdot}{\cdot \cdot} \cdots \cdot \\
 & \cdot \dfrac{\cdot}{\cdots} \cdot c \\
 & \cdot \rfloor ... - Br 
\end{array}
 \ +\ \dots - Br - Br \rightarrow \cdot \cdot \cdots \dfrac{\cdot}{\cdots} \mathrm{Fe} -
\begin{array}{c}
\cfrac{\cdot}{\cdots} \cdots \\
-\dfrac{\cdots}{\cdots} 
\\ \rfloor
\end{array}
 \  Br \cdot \left(\dfrac{Br}{\mathrm{Re}+} 
_{Br} 
\end{array}
 \dfrac{\cdot \cdot}{\cdots}
\)
\]

Which reactant is the Lewis acid and which is the Lewis base?

- [ ] Br₂ is the Lewis acid.
- [ ] FeBr₃ is the Lewis acid.
- [ ] FeBr₃ is the Lewis base.
- [ ] Br₂ is the Lewis base.


**Explanation:**
- **Reactants:**
  - One molecule of iron(III) bromide (FeBr₃) with Lewis structures of each bromine atom having four lone pairs.
  - One molecule of bromine (Br₂) depicted with each bromine atom having three lone pairs.

- **Products:**
  - The product indicates a complex where one of the bromine atoms from Br₂ forms a coordinate bond with FeBr₃ through its lone pair, resulting in an FeBr₄ complex ion with a bromine cation (Br⁺).

**Key Concepts:**
- **Lewis Acid:** A substance that can accept a pair of electrons to form a new bond. FeBr₃ acts as a Lewis acid because it accepts an electron pair from Br₂.
- **Lewis Base:** A substance that can donate a pair of electrons to form a new bond. Br₂ acts as a Lewis base because it donates an electron pair to FeBr
Transcribed Image Text:**Question 10 of 22** Consider the given reaction. \[ \begin{array}{c} \begin{array}{cc} & \cdot \cdot \cdot \cdot \dots \dfrac{\cdot \cdot \cdot \cdot}{\cdot \cdot} \cdots \cdot \\ & \cdot \dfrac{\cdot}{\cdots} \cdot c \\ & \cdot \rfloor ... - Br \end{array} \ +\ \dots - Br - Br \rightarrow \cdot \cdot \cdots \dfrac{\cdot}{\cdots} \mathrm{Fe} - \begin{array}{c} \cfrac{\cdot}{\cdots} \cdots \\ -\dfrac{\cdots}{\cdots} \\ \rfloor \end{array} \ Br \cdot \left(\dfrac{Br}{\mathrm{Re}+} _{Br} \end{array} \dfrac{\cdot \cdot}{\cdots} \) \] Which reactant is the Lewis acid and which is the Lewis base? - [ ] Br₂ is the Lewis acid. - [ ] FeBr₃ is the Lewis acid. - [ ] FeBr₃ is the Lewis base. - [ ] Br₂ is the Lewis base. **Explanation:** - **Reactants:** - One molecule of iron(III) bromide (FeBr₃) with Lewis structures of each bromine atom having four lone pairs. - One molecule of bromine (Br₂) depicted with each bromine atom having three lone pairs. - **Products:** - The product indicates a complex where one of the bromine atoms from Br₂ forms a coordinate bond with FeBr₃ through its lone pair, resulting in an FeBr₄ complex ion with a bromine cation (Br⁺). **Key Concepts:** - **Lewis Acid:** A substance that can accept a pair of electrons to form a new bond. FeBr₃ acts as a Lewis acid because it accepts an electron pair from Br₂. - **Lewis Base:** A substance that can donate a pair of electrons to form a new bond. Br₂ acts as a Lewis base because it donates an electron pair to FeBr
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