Question 10 For the standard normal variable Z, find 20.09. 20.09 (Round the answer to 2 decimal places) ^
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- Find the area of the indicated region under the standard normal curve. -1.5 & 0.9.The data show the bug chirps per minute at different temperatures. Find the regression equation, letting the first variable be the independent (x) variable. Find the best-predicted temperature for a time when a bug is chirping at the rate of 3000chirps per minute. Use a significance level of 0.05. What is wrong with this predicted value? Chirps in 1 min 1004 952 1237 1116 1177 1249 Temperature (°F) 83.1 76 95.1 87.5 92.1 88.4 What is the regression equation? (^ over y)=_____+_____x (Round the x-coefficient to four decimal places as needed. Round the constant to two decimal places as needed.) What is the best-predicted temperature for a time when a bug is chirping at the rate of 3000chirps per minute? The best-predicted temperature when a bug is chirping at 3000 chirps per minute is ____°F. (Round to one decimal place as needed.) What is wrong with this predicted value? Choose the correct answer below. A. It is…CV = (σ/mean) --> standard deviation / mean.Express the above equation carefully?
- uppose the lengths of human pregnancies are normally distributed with μ=266 days and σ=16 days. Complete parts (a) and (b) below. (a) The figure to the right represents the normal curve with μ=266 days and σ=16 days. The area to the left of X=235 is 0.0263. Provide two interpretations of this area. Provide one interpretation of the area using the given values. Select the correct choice below and fill in the answer boxes to complete your choice. (Type integers or decimals.) A. The proportion of human pregnancies that last more than nothing days is nothing. B. The proportion of human pregnancies that last less than days is X 266 235 A normal curve has a horizontal axis labeled "X" and two horizontal coordinates, 235 and 266. The curve's peak is near the top of the graph at horizontal coordinate 266. Two vertical line segments run from the horizontal axis to the curve at 235 and 266. The area under the curve to…The body weight of a healthy 3-month old colt should be about µ = test the claim that the weight of a wild Nevada colt (3-months old) is more than 60 kg. 60kg Suppose you want to State in words what a Type I Error is. State the mean weight of a wild Nevada (3-month old) colt is less than 60 Kg when in fact the mean weight of a wild Nevada colt (3-month old) is more than or equal to 60 kg. State the mean weight of a wild Nevada (3-month old) colt is more than 60 Kg when in fact the mean weight of a wild Nevada colt (3-month old) is less than or equal to 60 kg. State the mean weight of a wild Nevada (3-month old) colt is equal to 60 Kg when in fact the mean weight of a wild Nevada colt (3-month old) is not equal to 60 kg. State the mean weight of a wild Nevada (3-month old) colt is less than or equal to 60 Kg when in fact the mean weight of a wild Nevada colt (3-month old) is more than 60 kg.uestion 2: Write uses of the standard deviation
- Find the area of the shaded region the graph to the right to pics IQ scores of adults and those scores are normally distributed with a mean of 100 and a standard deviation of 15.Please identify the correct answer for the following question: "Why do we take the square root of the mean squared error to calculate the root mean squared error?" O To lower down the error O To normalize the error unit O None of themThe trunk diameter, in centimeters, of a certain variety of pine tree is represented by X~N(150, 30). What is the 75th percentile of trunk diameters? Round to two decimal places.
- When finding the area of a z score how do you know when to add or subtract the .5 or 1. I am very confused on this. I know more than half of the time you add .5 but then sometimes you also subtract from 1. In terms I am talking about Std. Normal Distribution if I am confusing you.Calculate the t-value for a mean for the following u – u0 = 15.00n = 25sx = 10.00The Z-score tells you the number of standard deviations away from the mean (and in what direction) a data value is. The formula: Z = *- can be used to find the Z-score for a single member of the population. Notice X - μ tells you the signed distance the data value (X) is from the mean. When you divide that by the size of each chunk (the standard deviation) you are measuring the distance in units of the size of the standard deviations (how many standard deviations fit in the distance between the data value and the mean) - which gives you the Z-score. The formula X = μ+Z.o can be used to find the value in the population when given the Z-score (signed number of standard deviations). Notice that Z. tells you how far from the mean the data value is (since Z is the number of standard deviations and is the size of each standard deviation the product tells the total distance). So adding the distance from the mean to the mean gives the location along the number line for the data value. A…