Question 1. The primary of a 1000 kVA, 11 / 3.3 kV three-phase transformer is connected in star and the secondary in delta. The resistances per phase of these windings are given as 0.375 Ω for the primary winding, 0.095 Ω for the secondary winding, and the leakage reactances per phase are 9.5 Ω for the primary winding and 2 Ω for the secondary winding. Calculate the voltage value and input power that must be applied to the primary when the secondary winding ends of the transformer are short-circuited. (In case of short circuit, the middle arm in the equivalent circuit will be neglected.)
Question 1. The primary of a 1000 kVA, 11 / 3.3 kV three-phase transformer is connected in star and the secondary in delta. The resistances per phase of these windings are given as 0.375 Ω for the primary winding, 0.095 Ω for the secondary winding, and the leakage reactances per phase are 9.5 Ω for the primary winding and 2 Ω for the secondary winding. Calculate the voltage value and input power that must be applied to the primary when the secondary winding ends of the transformer are short-circuited. (In case of short circuit, the middle arm in the equivalent circuit will be neglected.)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question 1. The primary of a 1000 kVA, 11 / 3.3 kV three-phase transformer is connected in star and the secondary in delta. The resistances per phase of these windings are given as 0.375 Ω for the primary winding, 0.095 Ω for the secondary winding, and the leakage reactances per phase are 9.5 Ω for the primary winding and 2 Ω for the secondary winding. Calculate the voltage value and input power that must be applied to the primary when the secondary winding ends of the transformer are short-circuited. (In case of short circuit, the middle arm in the equivalent circuit will be neglected.)
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