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Question 1. The homogeneous gate shown in Figure consists of one quarter of a circular cylinder and is used to maintain a water depth of 6+a/10 m. That is, when the water depth exceeds 6 + a/10 m, the gate opens slightly and lets the water flow under it. Determine the weight of the gate per meter of length. (y-9,81 KN/m³). Pivot 6+ b/10 m 2+ a/10m 4R 3x = = 0.05488R I =-0.01647R Hint: le) Quarter-circle

Question 1. The homogeneous gate shown in Figure consists of one quarter of a circular cylinder and is used to maintain a water depth of 6+a/10 m. That is, when the water depth exceeds 6 + a/10 m, the gate opens slightly and lets the water flow under it. Determine the weight of the gate per meter of length. (y-9,81 KN/m³). Pivot 6+ b/10 m 2+ a/10m 4R 3x = = 0.05488R I =-0.01647R Hint: le) Quarter-circle

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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the value of figure is not 6+b/10.True value is 6+a/10.

a = 6

Question 1. The homogeneous gate shown in Figure consists of one quarter of a circular cylinder and is used to maintain a water depth of 6+a/10 m. That is, when the water depth exceeds 6 + a/10 m, the gate opens slightly and lets the water flow under it. Determine the weight of the gate per meter of length. (y-9,81 KN/m³). Pivot 6+ b/10 m 2+ a/10m 4R 3x = = 0.05488R I =-0.01647R Hint: le) Quarter-circle
Transcribed Image Text:Question 1. The homogeneous gate shown in Figure consists of one quarter of a circular cylinder and is used to maintain a water depth of 6+a/10 m. That is, when the water depth exceeds 6 + a/10 m, the gate opens slightly and lets the water flow under it. Determine the weight of the gate per meter of length. (y-9,81 KN/m³). Pivot 6+ b/10 m 2+ a/10m 4R 3x = = 0.05488R I =-0.01647R Hint: le) Quarter-circle
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