Question 1. Assuming that the bedding was originally horizontal, and that the blocks have rotated intact (rigidly), what was the original dip of the normal faults? . . . Question 2.Question 2. Calculate the elongation strain for this set of domino faults. Assume that bedding was originally horizontal. Each imbricate is exactly the same width. Bedding dips 20 degrees and the faults dip 40 degrees. Please both show and explain your work. . . . Question 3.Question 3. What would the bedding and fault dip be at 100% extension?
Question 1. Assuming that the bedding was originally horizontal, and that the blocks have rotated intact (rigidly), what was the original dip of the normal faults? . . . Question 2.Question 2. Calculate the elongation strain for this set of domino faults. Assume that bedding was originally horizontal. Each imbricate is exactly the same width. Bedding dips 20 degrees and the faults dip 40 degrees. Please both show and explain your work. . . . Question 3.Question 3. What would the bedding and fault dip be at 100% extension?
Applications and Investigations in Earth Science (9th Edition)
9th Edition
ISBN:9780134746241
Author:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Publisher:Edward J. Tarbuck, Frederick K. Lutgens, Dennis G. Tasa
Chapter1: The Study Of Minerals
Section: Chapter Questions
Problem 1LR
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Question
Question 1. Assuming that the bedding was originally horizontal, and that the blocks have
rotated intact (rigidly), what was the original dip of the normal faults?
.
.
.
Question 2.Question 2. Calculate the elongation strain for this set of domino faults. Assume that
bedding was originally horizontal. Each imbricate is exactly the same width. Bedding dips 20
degrees and the faults dip 40 degrees. Please both show and explain your work.
.
.
.
Question 3.Question 3. What would the bedding and fault dip be at 100% extension?
rotated intact (rigidly), what was the original dip of the normal faults?
.
.
.
Question 2.Question 2. Calculate the elongation strain for this set of domino faults. Assume that
bedding was originally horizontal. Each imbricate is exactly the same width. Bedding dips 20
degrees and the faults dip 40 degrees. Please both show and explain your work.
.
.
.
Question 3.Question 3. What would the bedding and fault dip be at 100% extension?
Transcribed Image Text:Bedding
Dip = 20°
Fault
Dip = 40⁰
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