Question 1. A chemist studied the concentration of a solution (Y) over time (2). Fifteen identical solutions were prepared. The solutions were randomly divided into five sets of three, and the five sets were measured, respectively after 1, 3, 5, 7, and 9 hours. (a) Without making any plots the chemist entered the data into R, fitted a simple linear regression model and then carried out a goodness of fit test. The following is the Analysis of Variance table he produced but with some figures missing. Analysis of Variance Table Response: y x Residuals Lack of fit Pure error Total Df Sum Sq Mean Sq F value 1 12.5971 13 2.770 14 15.5218 the model for oin (ii) Copy and complete the Analysis of Variance Table.
Question 1. A chemist studied the concentration of a solution (Y) over time (2). Fifteen identical solutions were prepared. The solutions were randomly divided into five sets of three, and the five sets were measured, respectively after 1, 3, 5, 7, and 9 hours. (a) Without making any plots the chemist entered the data into R, fitted a simple linear regression model and then carried out a goodness of fit test. The following is the Analysis of Variance table he produced but with some figures missing. Analysis of Variance Table Response: y x Residuals Lack of fit Pure error Total Df Sum Sq Mean Sq F value 1 12.5971 13 2.770 14 15.5218 the model for oin (ii) Copy and complete the Analysis of Variance Table.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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question 1.a)ii)
Transcribed Image Text:Question 1.
A chemist studied the concentration of a solution (Y) over time
(z). Fifteen identical solutions were prepared. The solutions were randomly divided into five
sets of three, and the five sets were measured, respectively after 1, 3, 5, 7, and 9 hours.
(a) Without making any plots the chemist entered the data into R, fitted a simple linear
regression model and then carried out a goodness of fit test. The following is the
Analysis of Variance table he produced but with some figures missing.
Analysis of Variance Table
Response: y
X
Residuals
Lack of fit
Pure error
Total
Df Sum Sq Mean Sq F value
1 12.5971
13
2.770
14 15.5218
simple
(ii) Copy and complete the Analysis of Variance Table.
GOD
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