Question 1: Write the following query in SQL: “Find (all) the celebrities with the most followers.” You should print the name of each celebrity and the corresponding number of followers. Note there may be more than one celebrity with the same number of followers. Question 2: Translate the following query into one English sentence: SELECT NAME FROM user WHERE email IN (SELECT email FROM celebrity WHERE email NOT IN (SELECT email FROM blurt

SQL Queries:   Given the following schema. Primary keys are underlined and highlighted in yellow and foreign keys are bold. The meaning of the relations is straightforward. Medical_Staff(MS_Id, MS_First, MS_Last, MS_PhoneNumber, MS_Occupation, Salary) Blood_Bank(Bank_Id, Bank_Name, Bank_Street, Bank_City, Bank_St, Bank_PhoneNumber) Donor(Donor_Id, Donor_First, Donor_Last, Donor_BloodType, Donor_City, Donor_St, DOB, TotalNumberOfDonations) Donation_Record(Donor_Id, Donation_Date, Donation_Amount) Employee(MS_Id, Bank_Id) Storage(Donor_Id, Donation_Date, Bank_Id)   Write SQL queries to answer the following questions:   a.Find the average donation amount for Sue Thompson (Donor Id = 3329) for the year 2018.                   b.Sum all donations by Bank for each State (i.e. the State the blood bank is located in, not the Donor).                     c.Find the name of the youngest donor and all the donations made in by that donor in 2020.

Topic: Database Software: SQLite Schema Table:   CREATE TABLE name_basics (nconst VARCHAR(45) NOT NULL, primaryName VARCHAR(45) NULL, birthYear YEAR(4) NULL, deathYear YEAR(4) NULL, age INT NULL, movieNum INT NULL, PRIMARY KEY (nconst));   CREATE TABLE attributes (attributeID INT NOT NULL,attribute VARCHAR(45) NOT NULL,PRIMARY KEY (attributeID)); CREATE TABLE attributes_collection (akasID INT NOT NULL,attributeID INT NOT NULL,PRIMARY KEY (akasID, attributeID),CONSTRAINT attributeIDFOREIGN KEY (attributeID)REFERENCES attributes (attributeID)ON DELETE NO ACTIONON UPDATE NO ACTION);CREATE TABLE crew_directors (crewID INT NOT NULL,nconst VARCHAR(45) NOT NULL,PRIMARY KEY (crewID, nconst),CONSTRAINT crewIDFOREIGN KEY (crewID)REFERENCES title_crew (crewID)ON DELETE NO ACTIONON UPDATE NO ACTION,CONSTRAINT nconstFOREIGN KEY (nconst)REFERENCES name_basics (nconst)ON DELETE NO ACTIONON UPDATE NO ACTION);CREATE TABLE crew_writers (crewID INT NOT NULL,nconst VARCHAR(45) NOT NULL,PRIMARY KEY…

A real-world SQL database sample should be provided and explained.