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Question 1: Which of the following would be a violation of the Large Enough Condition? (a) The population is Normal and the sample size is 100. (b) The population is Normal and the sample size is 10. c) The population is somewhat skewed and the sample size is 100. (d) The population is somewhat skewed and the sample size is 10.

Question 1: Which of the following would be a violation of the Large Enough Condition? (a) The population is Normal and the sample size is 100. (b) The population is Normal and the sample size is 10. c) The population is somewhat skewed and the sample size is 100. (d) The population is somewhat skewed and the sample size is 10.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
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Question 1: Which of the following would be a violation of the Large Enough Condition? (a) The population is Normal and the sample size is 100. (b) The population is Normal and the sample size is 10. (c) The population is somewhat skewed and the sample size is 100. (d) The population is somewhat skewed and the sample size is 10. Question 2: Suppose that µ = 30, o = 5, and a random sample of sizen = 100 is drawn. We want to use the Normal model to compute Pr(x > 35). What are the centre and spread of the corresponding Normal distribution? (a) E(x) = 30 and SD(x) = 5. (b) Е(x) = 30 and SD(x) = 0.5. (c) E(x) = 30 and SD(x) = 0.05. (d) E(x) = 35 and SD(x) = 5. (e) E(x) = 35 and SD(x) = 0.5. (f) E(x) = 35 and SD(x) = 0.05. Question 3: Suppose that X is Normal with µ = 10 and that a random sample is taken. This sample is of size n = 5 and has sample mean x = 12 and sample standard deviation s = 3. To find the probability of such a large sample mean occurring, we compute z = 1.49 and find that this sample occurs with probability 0.0681. What is wrong with this computation? (a) The observations do not satisfy the independence assumption. (b) The sample size is too small to use the Normal distribution. (c) We should be computing the left-hand side and thus the probability is 0.9319. (d) We can not use a Normal distribution for this calculation since we do not know o. Question 4: If the standard deviation of the sample mean is 30, with a sample size of 100, then in order to reduce the standard deviation of the sample mean to 15, you would need to: (a) Increase the sample size to 400 (b) Decrease the sample size to 50 (c) Increase the sample size to 200 (d) Change the population standard deviation to o = 150.
Transcribed Image Text:Question 1: Which of the following would be a violation of the Large Enough Condition? (a) The population is Normal and the sample size is 100. (b) The population is Normal and the sample size is 10. (c) The population is somewhat skewed and the sample size is 100. (d) The population is somewhat skewed and the sample size is 10. Question 2: Suppose that µ = 30, o = 5, and a random sample of sizen = 100 is drawn. We want to use the Normal model to compute Pr(x > 35). What are the centre and spread of the corresponding Normal distribution? (a) E(x) = 30 and SD(x) = 5. (b) Е(x) = 30 and SD(x) = 0.5. (c) E(x) = 30 and SD(x) = 0.05. (d) E(x) = 35 and SD(x) = 5. (e) E(x) = 35 and SD(x) = 0.5. (f) E(x) = 35 and SD(x) = 0.05. Question 3: Suppose that X is Normal with µ = 10 and that a random sample is taken. This sample is of size n = 5 and has sample mean x = 12 and sample standard deviation s = 3. To find the probability of such a large sample mean occurring, we compute z = 1.49 and find that this sample occurs with probability 0.0681. What is wrong with this computation? (a) The observations do not satisfy the independence assumption. (b) The sample size is too small to use the Normal distribution. (c) We should be computing the left-hand side and thus the probability is 0.9319. (d) We can not use a Normal distribution for this calculation since we do not know o. Question 4: If the standard deviation of the sample mean is 30, with a sample size of 100, then in order to reduce the standard deviation of the sample mean to 15, you would need to: (a) Increase the sample size to 400 (b) Decrease the sample size to 50 (c) Increase the sample size to 200 (d) Change the population standard deviation to o = 150.
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