QUESTION 1 Tube C Tube B 0.01 ml Given Tube A 0.1 ml 0.1 ml Freezer Tube Has 0.9 mL Has 0.9 mL Has 0.99 mL For the following dilution calculate: The dilution from tube B to tube C O 10^2 10^2 mL 10^-2 10^-2 mL

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Q: The amount of potassium chloride in 150 mL of 8.5% w/v potasisum chloride solution is _____ g.

A: 8.5% w/v means 8.5 g potassium chloride in 100 mL solution.

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Q: 170.0 mL of 0.12 M C2 H5NH2 with 285.0 mL of 0.20 M C2 H5 NH3 Cl

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A: a. Molarity of KCl = 0.247 M Molarity = number of moles (mol)Volume of the solution (L) 0.247 M =…

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A: Please find the attachment.

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A: N1 * V1 = N2 * V2 N1 * 15ml =0.125 N * 21.45 ml Normality of H3PO4 (N1)= 0.178 N

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Q: A sample of KHP (molar mass = 204.23 g/mol) required 28.0 mL of NaOH solution (0.0832 M) to reach a…

A: Given: The molar mass of KHP (potassium hydrogen phthalate) is 204.23 g/mol The volume of NaOH…

Q: 1. If 30.0 mL of 1.0 M CH3COOH and 5.0 mL of 1.0 M NaOH are mixed in a beaker, what is the change in…

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