QUESTION 1 To prove that p→q=T by v we have to show that v is true. contraposition contrapositive contradiction inverse QUESTION 2 To prove thatp→q=T by ve we have to show that when p is true, q is direct proof contradiction true false

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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**Question 1:**

To prove that \( p \rightarrow q = \text{T} \) by [dropdown options: contrapositive, contradiction, inverse], we have to show that [text box] is true.

**Question 2:**

To prove that \( p \rightarrow q = \text{T} \) by [dropdown options: direct proof, contradiction], we have to show that when \( p \) is true, \( q \) is [text box].

**Explanation of Options in Dropdown Menus:**

- **Question 1 Options:**
  - **Contrapositive:** For proving an implication \( p \rightarrow q \) by contrapositive, show that \( \neg q \rightarrow \neg p \) is true.
  - **Contradiction:** Assume that the implication is false and show that this assumption leads to a contradiction.
  - **Inverse:** Consider the inverse of the implication, \( \neg p \rightarrow \neg q \).

- **Question 2 Options:**
  - **Direct Proof:** Show that the conclusion \( q \) follows directly from the assumption \( p \).
  - **Contradiction:** Assume the conclusion is false and demonstrate that this leads to a contradiction.
  - Additional options of "true" and "false" relate to whether \( q \) being true or false affects the direct proof outcome.
Transcribed Image Text:**Question 1:** To prove that \( p \rightarrow q = \text{T} \) by [dropdown options: contrapositive, contradiction, inverse], we have to show that [text box] is true. **Question 2:** To prove that \( p \rightarrow q = \text{T} \) by [dropdown options: direct proof, contradiction], we have to show that when \( p \) is true, \( q \) is [text box]. **Explanation of Options in Dropdown Menus:** - **Question 1 Options:** - **Contrapositive:** For proving an implication \( p \rightarrow q \) by contrapositive, show that \( \neg q \rightarrow \neg p \) is true. - **Contradiction:** Assume that the implication is false and show that this assumption leads to a contradiction. - **Inverse:** Consider the inverse of the implication, \( \neg p \rightarrow \neg q \). - **Question 2 Options:** - **Direct Proof:** Show that the conclusion \( q \) follows directly from the assumption \( p \). - **Contradiction:** Assume the conclusion is false and demonstrate that this leads to a contradiction. - Additional options of "true" and "false" relate to whether \( q \) being true or false affects the direct proof outcome.
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