QUESTION 1 The gas-phase mass transfer coefficient for the evaporation of a drop of ethyl alcohol in a stream of air at 300 K and 1.2 bar pressure is kg = 2.4x10* kmol/(s)(m²)(mmHg). (1) Calculate the values of the mass transfer coefficient if the driving force is expressed in terms of difference in (i) mole fraction of alcohol in the gas phase (ii) mole ratio of alcohol and (iii) concentration of alcohol in kmol/m (ii) Express kg in (i) Ibmol/(ft)(s)(psi) (i)lbmol/(ft)(h)(inch Hg)

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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QUESTION 1
The gas-phase mass transfer coefficient for the evaporation of a drop of ethyl alcohol in a
stream of air at 300 K and 1.2 bar pressure is kg = 2.4x10 kmol/(s)(m?)(mmHg).
(i)
Calculate the values of the mass transfer coefficient if the driving force is expressed
in terms of difference in (i) mole fraction of alcohol in the gas phase (ii) mole ratio of
alcohol and (ii) concentration of alcohol in kmol/m
(ii)
Express kg in (i) Ibmol/(ft)(s)(psi) (ii)lbmol/(ft)(h)(inch Hg)
Transcribed Image Text:QUESTION 1 The gas-phase mass transfer coefficient for the evaporation of a drop of ethyl alcohol in a stream of air at 300 K and 1.2 bar pressure is kg = 2.4x10 kmol/(s)(m?)(mmHg). (i) Calculate the values of the mass transfer coefficient if the driving force is expressed in terms of difference in (i) mole fraction of alcohol in the gas phase (ii) mole ratio of alcohol and (ii) concentration of alcohol in kmol/m (ii) Express kg in (i) Ibmol/(ft)(s)(psi) (ii)lbmol/(ft)(h)(inch Hg)
QUESTION 2
The equilibrium distribution of a solute C between solvents A and B (up to 30% of C in solution
in A) is given by
Y = 3.75 X,
where X and Y are the concentrations of C in A and B respectively, both in mass ratio unit that is,
mass of solute per unit mass of solute-free solvent. The solvents A and B are practically
immiscible.
It is required to calculate the amount od the solvent B required to separate 95% of C from 1000
kg of a 15% (by mass) solution of C in A for the following separation schemes (a) an ideal single
-stage contact (b) an ideal three-stage cross current contact, the amount of solvent used in
each stage being equal.
Transcribed Image Text:QUESTION 2 The equilibrium distribution of a solute C between solvents A and B (up to 30% of C in solution in A) is given by Y = 3.75 X, where X and Y are the concentrations of C in A and B respectively, both in mass ratio unit that is, mass of solute per unit mass of solute-free solvent. The solvents A and B are practically immiscible. It is required to calculate the amount od the solvent B required to separate 95% of C from 1000 kg of a 15% (by mass) solution of C in A for the following separation schemes (a) an ideal single -stage contact (b) an ideal three-stage cross current contact, the amount of solvent used in each stage being equal.
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